What goes in the empty box is 22 because they notes get multiplied by 2 to equal the time
According to the given, 1 in every 10 women has been a victim, therefore the probability of a victim of domestic abuse at some pint is
![p=\frac{1}{10} = 0.10](https://tex.z-dn.net/?f=p%3D%5Cfrac%7B1%7D%7B10%7D%20%3D%200.10)
We need to use Binomial distribution to take a randomly sampled of 25 women and asked each whether she has been a victim.
![f(x)= ^nC_x (p)^x (1-p)^{n-x}](https://tex.z-dn.net/?f=f%28x%29%3D%20%5EnC_x%20%28p%29%5Ex%20%281-p%29%5E%7Bn-x%7D)
Where x is the event that shows a victim of domestic abuse at some point.
We need to find the probability of these victim at least 2 has been victim of abuse, so
![P(x>=2) = 1- [P(x=0)+P(x=1)]](https://tex.z-dn.net/?f=P%28x%3E%3D2%29%20%3D%201-%20%5BP%28x%3D0%29%2BP%28x%3D1%29%5D)
![P(x>=2) = 1 - [^{25}C_0(0.10)^0(1-0.10)^{25-0}+^{25}C_1(0.10)^1(1-0.10)^{25-1}]](https://tex.z-dn.net/?f=P%28x%3E%3D2%29%20%3D%201%20-%20%5B%5E%7B25%7DC_0%280.10%29%5E0%281-0.10%29%5E%7B25-0%7D%2B%5E%7B25%7DC_1%280.10%29%5E1%281-0.10%29%5E%7B25-1%7D%5D)
![P(x>=2) = 1 - [0.07198+0.199]](https://tex.z-dn.net/?f=P%28x%3E%3D2%29%20%3D%201%20-%20%5B0.07198%2B0.199%5D)
![P(x>=2) = 0.72902](https://tex.z-dn.net/?f=P%28x%3E%3D2%29%20%3D%200.72902)
So the probability is 0.729
X/0.4 = 10x/4
21/9÷31/6 = 21•6/31•9
so solving the equation gives
X=84/465
If the radical, is the same in this case ✔️10, simply add or subtract the whole numbers or the coefficients of the radicals regularly, the solution would be 1✔️10 or simply ✔️10.
Marco = m Troy = rm is 20 more than r m = r + 20B: r + 20