6x - 12 = 8x + 14
2x = - 26
x = - 13
Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m
time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s
the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s
Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.
Answer:
F $35,000
Step-by-step explanation:
3,500 is 7% of 50,000 3500 multiplied by 10 years= 35,000
Answer:
Step-by-step explanation:
Given
comparing it with standard equation 
so 4a=1
so Focus of parabola is (0,0)
directrix
y=-a
here 
