Let the first number be = x
Then the second number = 2x
The third number = 2x - 5
Their sum = 55
This can be written in an equation as =
x + 2x + 2x - 5 = 55
= x + 2x + 2x = 55 + 5 ( transposing -5 from LHS to RHS changes -5 to +5 )
= x + 2x + 2x = 60
= 5x = 60
= x = 60 ÷ 5 ( transposing ×5 from LHS to RHS changes ×5 to ÷5 )
= x = 12
The first number = x = 12
The second number = 2x = 2 × 20 = 24
The third number = 2x - 5 = 24 - 5 = 19
Therefore , the three numbers are 12 , 24 and 19 .
P = 2L + 2W ....subtract 2L from both sides
P - 2L = 2W ...divide both sides by 2
(P - 2L) / 2 = W .....can also be written like (P/2) - L = W
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1 + sec^2(x)sin^2(x) = sec^2(x)
This becomes
1+tan^2(x) = sec^2(x) which is an identity
You could
1 + sin^2(x)/cos^2(x) = sec^2(x)
then
cos^2(x) + sin^2(x) = cos^2(x)sec^2(x)
1 = 1
What is it?
The IQR describes the middle 50% of values when ordered from lowest to highest. To find the interquartile range (IQR), first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.
How do you find IQR?
<em>Step 1: Put the numbers in order. ...</em>
<em>Step 2: Find the median. ...</em>
<em>Step 3: Place parentheses around the numbers above and below the median. Not necessary statistically, but it makes Q1 and Q3 easier to spot. ...</em>
<em>Step 4: Find Q1 and Q3. ...</em>
<em>Step 5: Subtract Q1 from Q3 to find the interquartile range.</em>
