Which function could produce the graph shown below?

Mathematics

1 answer:

Naily [24]3 years ago

4 0

Answer:

It is the third option. I just got it correct.

Step-by-step explanation:

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Find the exact length of the third side.<br> 5<br> 3

grandymaker [24]

I'm going to assume you want to find the third side of a triangle. We can use the pythagorean theorem to solve; a^2 + b^2 = c^2

a = 5

b = 3

c = ?

Solve.

5^2 + 3^2 = c^2

25 + 9 = c^2

34 = c^2

√34 = √c^2

5.8 ≈ c

Best of Luck!

5 0

4 years ago

A student wants to conduct an experiment to see how quickly information can travel. On Day 1 of the experiment, the student tell

Aliun [14]

3 people know a fact in 1st day.
In 2nd day they share it with 3 people each=3×3
Now 3×3 people shares it with 3 people each. and so on...
So,
3+3²+3³+3⁴+3^5+3^6+3^7
=3279 no of people altogether , will hear from 1st day to 7th day...
On the day 7,no of people who will hear the fact=3^7=2187

7 0

3 years ago

Let v be the event that a computer contains a virus, and let w be the event that a computer contains a worm. suppose p(v ) = 0.1

ladessa [460]

We have been given that the probability of a computer containing a virus P(v) is 0.15 and probability of computer containing a worm P(w) is 0.05.

We are also told that probability of computer containing either virus or worm $P(v\cup w)$ is 0.17.

(a) To find out the probability that the computer contains both a virus and a worm we will use probability formula,

$P(A)+P(B)=P(A\cup B)+P(A\cap B)$

Now let us substitute our given values in this formula.

$0.15+0.05=0.17+P(A\cap B)$

$P(A\cap B)=0.20-0.17=0.03$

Therefore, probability that that the computer contains both a virus and a worm is 0.03.

(b) To find out the probability that the computer contains neither a virus nor a worm we will subtract the probability of computer containing both virus and worm from 1.

$\text{Probability that computer contains neither virus nor worm}=1-P(v\cup w)\\$