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4 years ago

5

WILL MARK BRAINLIEST!

2 answers:

poizon [28]4 years ago

8 0

no they are both incorrect by my understanding of your question use the Pythagorean theorem a^2 + b^2 =c^2 therefore 7^2 +x^2 = 13^2 or 49+x=169 then solve normally 169-49=120 √120 =5

The answer is 5

Georgia [21]4 years ago

3 0

Sheridan is correct. She followed all of the correct steps of the Pythagorean Theory. The reason that Jayden was wrong is because he used the hypotenuse of the triangle as "b" in the formula instead of using it as "c" which is where they hypotenuse always has to go in this formula.

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X+3y=24<br><br> Please solve super fast

adoni [48]

Step-by-step explanation:

x+3y=24

3y/3=24/3

x+y=8

divide x to both side not to y

y=-x +8

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3 years ago

Find the general indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.

Maru [420]

Answer:

$9\text{ln}|x|+2\sqrt{x}+x+C$

Step-by-step explanation:

We have been an integral $\int \frac{9+\sqrt{x}+x}{x}dx$ . We are asked to find the general solution for the given indefinite integral.

We can rewrite our given integral as:

$\int \frac{9}{x}+\frac{\sqrt{x}}{x}+\frac{x}{x}dx$

$\int \frac{9}{x}+\frac{1}{\sqrt{x}}+1dx$

Now, we will apply the sum rule of integrals as:

$\int \frac{9}{x}dx+\int \frac{1}{\sqrt{x}}dx+\int 1dx$

$9\int \frac{1}{x}dx+\int x^{-\frac{1}{2}}dx+\int 1dx$

Using common integral $\int \frac{1}{x}dx=\text{ln}|x|$ , we will get:

$9\text{ln}|x|+\int x^{-\frac{1}{2}}dx+\int 1dx$

Now, we will use power rule of integrals as:

$9\text{ln}|x|+\frac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+\int 1dx$

$9\text{ln}|x|+\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2x^{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2\sqrt{x}+\int 1dx$

We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

$9\text{ln}|x|+2\sqrt{x}+x+C$

Therefore, our required integral would be $9\text{ln}|x|+2\sqrt{x}+x+C$ .

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3 years ago

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Charra [1.4K]

Answer:

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3 years ago

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hoa [83]

Answer is <span>A.
associative property

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3 years ago

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raketka [301]

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3 years ago

Read 2 more answers