Let x be the first number each pair and y is the second of each
As you see 1x is 3y
And. 2x is 3*3y= 9y
3x = 3*3*3y= 27y
Last 4x =3*3*3*3y= 81y
So y = 3^x
ANSWER
B. 10
EXPLANATION
We need to find the value of x first.
It was given that the perimeter of triangle XYZ is 24.
This means that:
XY+YZ+XZ=24
we substitute the expression in terms of x to get;
This implies that
Divide both sides by 4 to get;
|WY|=|ZX|=13-3=10
The solution is 2sqrt77/77. You just fill in 2/3 for the x's. When you do that, you do that you get (2/3)/sqrt(9-[2/3]^2) which, simplified, is (2/3)/sqrt(9-[4/9]). Now use the common denominator under the radical of 9 to get (2/3)/sqrt([81-4]\9). Simplifying even further gives you (2/3)/([sqrt(77)]/3). Now do that division by multiplying 2/3 by the reciprocal of ([sqrt(77)]/3) to get 2/sqrt77. I rationalized the denominator to get that result up there.
-5x + 5y = 40 -20x +20y =160 -5x + 5(8) = 40
4x + 3y = 24 20x +15y =120 -5x + 40 = 40
35y = 280 -5x =0
y = 8 x = 0
Hope you understood this
Answer:
D
Step-by-step explanation:
