Answer:
1*65
5*13
that is all answers one through twelve
Step-by-step explanation:
Let;
A(-8,6) B(6,6) C(6, -4) D(-8, -4)
Let's find the length AB
x₁= -8 y₁=6 x₂=6 y₂=6
We will use the distance formula;
![d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
![=\sqrt[]{(6+8)^2+(6-6)^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B%286%2B8%29%5E2%2B%286-6%29%5E2%7D)
![=\sqrt[]{14^2+0}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B14%5E2%2B0%7D)

Next, we will find the width BC
B(6,6) C(6, -4)
x₁= 6 y₁=6 x₂=6 y₂=-4
substitute into the distance formula;
![d=\sqrt[]{(6-6)^2+(-4-6)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%5B%5D%7B%286-6%29%5E2%2B%28-4-6%29%5E2%7D)
![=\sqrt[]{(-10)^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B%28-10%29%5E2%7D)
![=\sqrt[]{100}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B100%7D)

Area = l x w
= 14 x 10
= 140 square units
Answer:
Interval [b,c] and interval [c,d]
Step-by-step explanation:
a(-5,0)
b(-1,2)
c(4,3)
d(11,4)
The average rate of change is the the total rise over the total run.
The Rise means the vertical increase and the Run means horizontal incease.
For interval [a,b]
rate of change is 
For [b,c]

For [c,d]

Answer:
8c - 7r + 10p - 20e
Step-by-step explanation:
Subtract (20c + 15r + 75p + 50e) - (12c + 22r + 65p + 70e)
(20c + 15r + 75p + 50e) - (12c + 22r + 65p + 70e)
Open bracket
20c + 15r + 75p + 50e - 12c - 22r - 65p - 70e
Collect like terms
= 20c - 12c + 15r - 22r + 75p - 65p + 50e - 70e
= 8c - 7r + 10p - 20e