The brand of cartridge which is the best buy us the brand with the lowest unit price which is brand A.
<h3>Unit price</h3>
Brand A
Cost = $20
pages = 200
Unit price = $20/200
= $0.1 per page
Brand B:
Cost = $25
Pages = 125
Unit price = $25/125
= $0.2 per page
Brand C:
Cost = $30
Pages = 150
Unit price = $30 / 150
= $0.2 per page
Brand D:
Cost = $35
Pages = 250
Unit price = $35 / 250
= $0.14 per page
Therefore, the brand of cartridge which is the best buy us the brand with the lowest unit price which is brand A.
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we know that a₁ = 1, and aₙ = aₙ₋₁ + 2, is another way of saying, we add 2 to get the next term, namely, 2 is the common difference.
![\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ a_1=1\\ d=2\\ n=7 \end{cases} \\\\\\ a_7=1+(7-1)2\implies a_7=1+12\implies a_7=13](https://tex.z-dn.net/?f=%5Cbf%20n%5E%7Bth%7D%5Ctextit%7B%20term%20of%20an%20arithmetic%20sequence%7D%0A%5C%5C%5C%5C%0Aa_n%3Da_1%2B%28n-1%29d%5Cqquad%0A%5Cbegin%7Bcases%7D%0An%3Dn%5E%7Bth%7D%5C%20term%5C%5C%0Aa_1%3D%5Ctextit%7Bfirst%20term%27s%20value%7D%5C%5C%0Ad%3D%5Ctextit%7Bcommon%20difference%7D%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Aa_1%3D1%5C%5C%0Ad%3D2%5C%5C%0An%3D7%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0Aa_7%3D1%2B%287-1%292%5Cimplies%20a_7%3D1%2B12%5Cimplies%20a_7%3D13)
Answer:
90.
Step-by-step explanation:
We have two lines of code:
y ← x + x + x + x + x
z ← y + y + y
and, x=6 before the execution. Then, when the program starts to run we obtain:
y ← 6 + 6 + 6 + 6 + 6
y ← 30
z ← 30+30+30
z ← 90.
Then, the value of z after excecution is 90.
1/6 pound of chocolate for each person ( 1/2 / 3 ).