Which expression is a binomial? A. P(to the second power) B. 3W. C. 3W+1. D. 3P(to the second power)+2P+2

These are the round-trip distances that city buses traveled on different routes each month. Calculate the distance, in miles, th

prohojiy [21]

I think you have to use the distance formula

4 0

3 years ago

When 2(3/5 x + 2/3 y - 1/4 x -1 1/2 y + 3 )is simplified, what is the resulting expression?

vovangra [49]

Answer:

Simplifying the expression: $2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3)$ we get $\mathbf{42x-100y-360}$

Step-by-step explanation:

We need to simplify the expression: $2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3)$

First we will solve terms inside the bracket

$2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3)$

Converting mixed fraction $1\frac{1}{2} y$ into improper fraction, we get: $\frac{3}{2}y$

Replacing the term:

$2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-\frac{3}{2}y +3)$

Now, taking LCM of: 5,3,4,2 we get 60

Now multiply 60 with each term inside the bracket

$2(\frac{3}{5}x\times60+\frac{2}{3}y\times60-\frac{1}{4}x\times60-\frac{3}{2}y\times60 +3\times60)\\2(3x\times12+2y\times20-1x\times15-3x\times30-3\times60)\\2(36x+40y-15x-90y-180)$

Now, combine like terms

$2(36x-15x-90y+40y-180)\\2(21x-50y-180)$

Now, multiply all terms with 2

$42x-100y-360$

So, Simplifying the expression: $2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3)$ we get $\mathbf{42x-100y-360}$

3 0

3 years ago

Given the function f(x) = x3 + 2x2 − 3x − 5, what is resulting function when f(x) is shifted to the right 1 unit?

cluponka [151]

When shifted to the right 1 unit it would be:
f(x - 1) = (x - 1)^3 + 2(x - 1)^2 - 3(x - 1) - 5
= (x^3 - 3x^2 + 3x - 1) + 2(x^2 - 2x + 1) - 3(x - 1) - 5 
= x^3 - 3x^2 + 2x^2 + 3x - 4x - 3x - 1 + 2 + 3 - 5 
= x^3 - x^2 - 4x - 1
I hope this helps

5 0

3 years ago

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Identify the translation of the figure with the vertices P(−4,−5), L(1,−7), and K(−9,8), along the vector <−6, 3>.

jarptica [38.1K]

Answer:

P ′(−10, −2), L ′(−5, −4), K ′(−15, 11)

Step-by-step explanation:

The translation vector, ⟨−6,3⟩, can be used to derive a rule for the translation of the coordinates: (x,y)→(x−6,y+3).

Apply the rule to translate each of the three preimage vertices to the image vertices.

P(−4,−5)→P'(−10,−2)

L(1,−7)→L'(−5,−4)

K(−9,8)→K'(−15,11)

Therefore, P'(−10,−2), L'(−5,−4), N'(−15,11) is the translation of the figure with the vertices P(−4,−5), L(1,−7), and K(−9,8), along the vector ⟨−6,3⟩.

4 0

2 years ago

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20) If a quadratic equation cannot be factored then

PolarNik [594]

Answer:

?

Step-by-step explanation:

I'm confused, what are you asking?

7 0

3 years ago