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3 years ago

Endent Practice

Mathematics

1 answer:

Vikki [24]3 years ago

6 0

Answer:

Part A: The unit that would be best to describes the situations is to the mile

Part B: 4 significant figures

Part C: 1,450 miles

Part D: He is not correct

Step-by-step explanation:

Part A: By unit conversion, we have;

1 mile = 1,760 yards

Given that the distance from Ottawa, Canada to Jackson Mississippi is 2,552,000 yards it would best simplified into miles

Part B: The number of significant digits in the reporters estimate are the non-zero digits before the zeros in the number figure which are 2, 5, 5, and 2 or 4 significant figures

Part C: 2,552,000 yards = 2,552,000 yards/(1,760 yards/mile) = 1,450 miles

Part D: Given that the distance from Jackson to Tucson = 7,159,680 feet, we have;

1 mile = 5,280 feet

Therefore;

7,159,680 feet = 7,159,680 feet/(5,280 feet/mile) = 1,356 miles

Therefore, the claim that the distance from Jackson to Tucson which is 1,356 miles is further than the distance from Ottawa, Canada to Jackson Mississippi which is 1,450 miles is not correct because;

The distance from Jackson to Tucson 1,356 miles $\ngtr$ 1,450 miles which is the distance from Jackson to Ottawa

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Answer:

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Parameters given stated that;

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p° ≤ $\frac{315}{500}$ =0.63 and the region region as p°>0.63 (where p° is known as the sample proportion)

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where p° is represented as pI in the subsequent calculated steps below

= P $[\frac{p°-p}{\sqrt{\frac{p(1-p)}{n}}} >\frac{0.63-p}{\sqrt{\frac{p(1-p)}{n}}} |p=0.6]$

= P $[\frac{p°-0.6}{\sqrt{\frac{0.6(1-0.6)}{500}}} >\frac{0.63-0.6}{\sqrt{\frac{0.6(1-0.6)}{500}}} ]$

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where p° is represented as pI in the subsequent calculated steps below

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