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Savatey [412]
3 years ago
7

Aaron and Belinda went swimming. Aaron swam 575 meters. This is 150 more meters than Belinda swam. Write and solve an addition e

quation to find the number of of meters that Belinda swam.
Mathematics
1 answer:
creativ13 [48]3 years ago
0 0

Answer:

Belinda swam 425 meters

Step-by-step explanation:

575=150+x

575-150=x+150-150

425=x

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English
larisa86 [58]

Answer:

6 square feet

Step-by-step explanation:

Carpet has w= 8 ft and l = 12 ft

Reduced carpet has w' = 2 ft

<u>Reduction factor is </u>

  • 8/2 = 4

<u>Then </u>

  • l' = l/4 = 12/4 = 3 ft

<u>Area of small carpet</u>

  • S = 2*3 = 6 ft²
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5x<br><img src="https://tex.z-dn.net/?f=5x%20%7B%20%7B%20%3D%2045%7D%5E%7B%3F%7D%20%7D%5E%7B2%7D%20" id="TexFormula1" title="5x
Ilia_Sergeevich [38]
\bf 5x=45^2\implies x=\cfrac{45^2}{5}\implies x=\cfrac{2025}{5}\implies x=405
8 0
3 years ago
What is the horizontal asymptote of f(x)=-2x/x+1<br> A.-2<br> B.-1<br> C.0<br> D.1
Mrrafil [7]
A horizontal asymptote of a function f(x) is given by y = lim f(x) as x --> ∞ and x --> –∞. In this case, 
\lim_{x \to \infty}  \frac{-2x}{x+1} = \lim_{x \to \infty}  \frac{-2x}{x(1+ \frac{1}{x} )}\\&#10;=\lim_{x \to \infty}  \frac{-2}{1+ \frac{1}{x} }\\&#10;= -2&#10;

Thus, the horizontal asymptote of f(x) is y = –2.
7 0
3 years ago
Read 2 more answers
What tose by mean in mathematics?
Bumek [7]
The misused form but it is really the mean the arithmetical form of mean
6 0
3 years ago
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Consider the graph of the function f(x) = 25
trasher [3.6K]

Considering it's horizontal asymptote, the statement describes a key feature of function g(x) = 2f(x) is given by:

Horizontal asymptote at y = 0.

<h3>What are the horizontal asymptotes of a function?</h3>

They are the limits of the function as x goes to negative and positive infinity, as long as these values are not infinity.

Researching this problem on the internet, the functions are given as follows:

  • f(x) = 2^x.
  • g(x) = 2f(x) = 2(2)^x

The limits are given as follows:

\lim_{x \rightarrow -\infty} g(x) = \lim_{x \rightarrow -\infty} 2(2)^x = \frac{2}{2^{\infty}} = 0

\lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} 2(2)^x = 2(2)^{\infty} = \infty

Hence, the correct statement is:

Horizontal asymptote at y = 0.

More can be learned about horizontal asymptotes at brainly.com/question/16948935

#SPJ1

3 0
1 year ago
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