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7nadin3 [17]
3 years ago
15

2x - y = 10

Mathematics
2 answers:
Zolol [24]3 years ago
7 0
You can plug -x - 1 for y in the first equation

2x - (-x - 1) = 10

2x + x + 1 = 10

Combine

3x = 9

Divide

x = 3

Plug 3 for x in any equation ( I'll use th second equation )

y = - (3) - 1

y = - 3 - 1 = -4

x = 3 ; y = -4

(3, -4)
cupoosta [38]3 years ago
7 0
2x - y = 10      .............(a)

y = -x - 1            ...........(b)

Substitute y = - x - 1 into equation (a) 

<span>2x - y = 10
</span>
2x - (-x - 1) = 10

2x + x + 1 = 10

3x + 1 = 10

3x = 10 - 1

3x = 9

x = 9/3 = 3.             x = 3 

Recall, y = -x - 1 = -3 - 1 = -4

Hence solution (x, y) = (3, -4)
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5 0
2 years ago
The sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab 2. if one addend is –5a2b2 12a2b – 5, what is the other addend? 15a2b2 –
Brrunno [24]

The other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab  is 15a²b²- 20a²b + 6ab² - 4ab + 7.

<h3>What is polynomial?</h3>

Polynomial equations is the expression in which the highest power of the unknown variable is n (n is real number).

The sum of two polynomials is,

10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2

The one polynomial addend is,

-5a^2b^2 +12a^2b - 5

Let suppose the other polynomial addend is f(a,b). Thus,

(-5a^2b^2 +12a^2b - 5)+f(a,b)=(10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2)

Isolate the second polynomial as,

f(a,b)=(10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2)-(-5a^2b^2 +12a^2b - 5)\\f(a,b)=10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2+5a^2b^2 -12a^2b + 5

Arrange the like terms as,

f(a,b)=10a^2b^2+5a^2b^2 - 8a^2b -12a^2b+ 6ab^2 - 4ab + 2+5\\f(a,b)=15a^2b^2- 20a^2b + 6ab^2 - 4ab + 7

Hence, the other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab  is 15a²b²- 20a²b + 6ab² - 4ab + 7.

Learn more about polynomial here;

brainly.com/question/24380382

7 0
2 years ago
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dangina [55]

Answer:

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Step-by-step explanation:

5 0
3 years ago
PLEASE HELP AS SOON AS POSSIBLE! Please look at the attached image, I greatly appreciate it!
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Answer:

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Step-by-step explanation:

6 0
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