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svp [43]
4 years ago
9

Fabio is designing a flashlight that uses a parabolic reflecting mirror and a light source. The shape of the mirror can be model

ed by (x-2)^2=10(y-3), where x and y are measured in inches. Where is the focus of the flashlight?
A. (–2, –0.5)
B. (2, –5.5)
C. (2, 5.5)
D. (5.5, 2)
Mathematics
2 answers:
iragen [17]4 years ago
6 0
We are given the parabolic equation
(x - 2)² = 10 (y - 3)
The general formula for the parabolic equation is
(x - h)² = 4a (y - k)
where a is the length of the focus
So,
4a = 10
a = 10/4
a = 2.5

The focus is 2.5
nevsk [136]4 years ago
4 0

Answer:

(2, 5.5)

Step-by-step explanation:

The standard form of parabola is :

(x - h)^2 = 4p (y - k) ---1

where the focus is (h, k + p)  

Now we are Fabio is designing a flashlight that uses a parabolic reflecting mirror and a light source.The shape of the mirror can be modeled by: (x-2)^2=10(y-3)

Now compare it with 1

h = 2

k=3

4p=10

p=\frac{10}{4} =2.5

Now Focus  is (h, k + p)  

So, the focus of the flash light = (2,3+2.5)

                                                   = (2,5.5)

Hence  the focus of the flashlight is  (2, 5.5)

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