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barxatty [35]
1 year ago
15

Bob's password consists of a non-negative single-digit number followed by a letter and another non-negative single-digit number

(which could be the same as the first one). What is the probability that Bob's password consists of an odd single-digit number followed by a letter and a positive single-digit number
Mathematics
1 answer:
maw [93]1 year ago
5 0

9/20 is the probability that Bob's password consists of an odd single-digit number followed by a letter and a positive single-digit number

It is given that bob's password consists of a non-negative single-digit number followed by a letter and another non-negative single-digit number (which could be the same as the first one).

P (odd single digit number )  =  ( 5 odd single digits / 10 non-negative single digits)  = (5/10)  = 1/2

P (positive single digit number ) =  (9 positive single digits / 10 non-negative single digits)  = 9/10

The total probability is   (1/2) (9/10)  =  9/20

Learn more about word problems here: brainly.com/question/21405634

#SPJ4

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\boxed { \text {Cosine Rule : } a^2 = b^2 + c^2 - 2bc \cos(A) }

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9² = 12² + 15² - 2 (12) (15) cos (B)

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81 = 369 - 360 cos (B)

360 cos (B) = 369 - 81

360 cos (B) = 288

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Answer: Cosine B = 0.8

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\boxed { \text {Cosine Rule : } a^2 = b^2 + c^2 - 2bc \cos(A) }

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12² = 15² + 9² - 2 (15)(9) cos (A)

144 = 225 + 81 - 270 Cos A

144 = 306 - 270 Cos A

270 Cos A = 162

Cos A = 3/5 or 0.6

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Answer: Cosine Angle A = 3/5

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Given that:

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