A force of 10 lb is required to hold a spring stretched 4 in. beyond its natural length. How much work is done in stretching it
1 answer:
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Answer:
Step-by-step Explanation:
Given:
∆UVW,
m < U = 33°
m < V = 113°
VW = u = 29 m
Required:
Area of ∆UVW
Solution:
Find side length UV using Law of Sines
U = 33°
u = VW = 29 m
W = 180 - (33+113) = 34°
w = UV = ?
Cross multiply
Divide both sides by sin(33) to make w the subject of formula
(rounded to nearest whole number)
Find the area of ∆UVW using the formula,
(to nearest tenth).
