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alexandr1967 [171]
2 years ago
11

813 divided by 4 and find remainder

Mathematics
2 answers:
Artemon [7]2 years ago
8 0
203 r 25 would be the answer
Mumz [18]2 years ago
4 0

Answer:

203.25 (1 = remainder)

Step-by-step explanation:

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Solve for x:<br> x³=23<br><br> Choose all that apply:<br><br> ∛23<br><br> 3<br><br> 1<br><br> 23/3
rosijanka [135]
Your answer is A. I have attached a photo of an explanation

6 0
2 years ago
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A school is selling tickets to their Spring theater production. Student tickets cost $6 each and non-student tickets cost $9 eac
I am Lyosha [343]

Answer:

x=137

y=525-137

y=388

Step-by-step explanation:

Let the student tickets be x

Let the geral Admission tickets be y

x+y=525

y=525-x

4x+6y=2876 (subsitute for y)

4x+6(525-x)=2876

 

4x+3150-6x=2876

-2x=-274

x=137

y=525-137

y=388

Hence, about 137 childern tickets were sold and 388 gernal admission tickets were sold.

Paul.

3 0
3 years ago
Read 2 more answers
A small regional carrier accepted 19 reservations for a particular flight with 17 seats. 14 reservations went to regular custome
Ludmilka [50]

Answer:

(a) The probability of overbooking is 0.2135.

(b) The probability that the flight has empty seats is 0.4625.

Step-by-step explanation:

Let the random variable <em>X</em> represent the number of passengers showing up for the flight.

It is provided that a small regional carrier accepted 19 reservations for a particular flight with 17 seats.

Of the 17 seats, 14 reservations went to regular customers who will arrive for the flight.

Number of reservations = 19

Regular customers = 14

Seats available = 17 - 14 = 3

Remaining reservations, n = 19 - 14 = 5

P (A remaining passenger will arrive), <em>p</em> = 0.52

The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 5 and <em>p</em> = 0.52.

(1)

Compute the probability of overbooking  as follows:

P (Overbooking occurs) = P(More than 3 shows up for the flight)

                                        =P(X>3)\\\\={5\choose 4}(0.52)^{4}(1-0.52)^{5-4}+{5\choose 5}(0.52)^{5}(1-0.52)^{5-5}\\\\=0.175478784+0.0380204032\\\\=0.2134991872\\\\\approx 0.2135

Thus, the probability of overbooking is 0.2135.

(2)

Compute the probability that the flight has empty seats as follows:

P (The flight has empty seats) = P (Less than 3 shows up for the flight)

=P(X

Thus, the probability that the flight has empty seats is 0.4625.

4 0
3 years ago
What is (7-7i) in polar form
jonny [76]
 z = 7√2 cos(7/8π) + 7√2i sin(7/8π) = 7√2e^(i7/8π)
4 0
3 years ago
Read 2 more answers
Toms house cost $100000 in the year 2000 in 2008 he sold his house for 125000 what was the percentage of change in the price of
Leno4ka [110]
There was a 125% change in the price of the house.

The changed price was an increase of from the original 100,000 therefore the answer can be concluded to be above 100%.

Anyways, to solve this problem you need to find what 125,000 is OF 100,000, meaning you need to divide. 125,000/100,000=1.25. 1.25 can then be changed into 125%.
8 0
3 years ago
Read 2 more answers
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