Answer:
Average rate of change 
Step-by-step explanation:
Given function is 
and we need to find average rate of change of the function from 
.
Average rate of change 
So,
Average rate of change
Hence, average rate of change of the function over the intervel is .
Answer:
Step-by-step explanation:
A clerk sold 70 centimeters of fabric to a customer. This clerk correctly filled out the invoice, writing:
1 point
a) 0.07 m
b) 0.070 m
c) 0.070 cm
d) 0.70 m
The clerk sold 70cm of fabrics
So, she want to filled the invoice but it length of fabrics sold must be in metre.
From metric units
100cm = 1m
Then,
70 cm = x
100cm = 1m
Cross multiply
70 cm × 1m = x × 100cm
Divide both side by 100cm
Then,
x = 70 cm × 1 m / 100cm
cm cancel out
x = 70 × 1m / 100
x = 70m / 100
x = 0.7m.
So, the correct answer is D.
To Portuguese
O funcionário vendeu 70cm de tecidos
Então, ela deseja preencher a fatura, mas o comprimento dos tecidos vendidos deve estar em metros.
De unidades métricas
100cm = 1m
Então,
70 cm = x
100cm = 1m
Multiplicação cruzada
70 cm × 1 m = x × 100 cm
Divida os dois lados por 100cm
Então,
x = 70 cm × 1 m / 100 cm
cm cancelar
x = 70 × 1m / 100
x = 70m / 100
x = 0,7 m.
Então, a resposta correta é D.
Plug g(x) in for every x in f(x) then substitute 4, you’ll get (f o g)(4) = 34
Answer:
a(n) = 13 - 2n
Step-by-step explanation:
The explicit formula variables are a(n) = a(1) + d (n - 1). The a(1) is your number you started out with, and the d is the common difference. From the recursive formula example, you see that your first number is 11 and your difference is -2.
1. Plug the numbers into the equation : a(n) = 11 - 2 (n - 1)
2. Distribute: a(n) = 11 - 2n + 2
3. Add like terms: a(n) = 13 - 2n
If you want to double check, you can plug 1 into n and see if you get 11. I did this, and I did so it should be correct. Hope this made sense! Have a great day :)
Answer:
41/3
Step-by-step explanation:
given that your waiting time for a bus in the morning is uniformly distributed on [0, 8], whereas waiting time in the evening is uniformly distributed on [0, 10] independent of morning waiting time.
Sum of both waiting times = X+Y
Where X = morning wait time is U(0.8) and
Y = evening wait time is U(0,10)
Since X and Y are independent
Var(x+y) = Var(x)+Var(y)
Var(x) = 
Var(Y) = 
Var(x+y) 
