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faust18 [17]
3 years ago
5

Factor the polynomial with GCF

Mathematics
1 answer:
Vlad [161]3 years ago
3 0

Answer:

3m^2

Step-by-step explanation:

Find the prime factors of each term in order to find the greatest common factor (GCF).

3m^2 p.s. i love bob the tomato;)

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Point B lies between points A and C, and all three points lie on point AC, which of the following is not true? A. Point B lies o
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Answer:

C. Point A lies on ray BC

Step-by-step explanation:

Points A and C can be connected by a segment which would be a measure of the distance between the points. Locating point B between AC, makes the three points lying on segment AC.

A ray extends from a point to infinity, a line extend to infinity on both sides, while a segment is known to have two endpoints. Therefore, points AC are the end points of the segment AC, and point B between this segment confirms that point B lies on the segment AC. Therefore, Point A lies on ray BC is not correct.

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The bisector of an obtuse angle forms right angles acute angles obtuse angles straight angles
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The radius of a cylinder is 7 c m and its height is 10 c m. Find curved surface area and volume.​
erma4kov [3.2K]

Answer:

  • CSA of the cylinder = 440 sq. cm

  • Volume of the cylinder = 1540 cu. cm

\\

Step-by-step explanation:

Given:

  • Radius of the cylinder = 7 cm
  • Height of the cylinder = 10 cm

\\

To Find:

  • Curved surface area
  • Volume

\\

Solution:

\\

Using formula:

\dashrightarrow \:  \:  { \underline{ \boxed{ \pmb{ \sf{ \purple{CSA  \: of  \: cylinder = 2\pi rh}}}}}}  \:  \star \\  \\

<em>Substituting the required values: </em>

\\

\dashrightarrow \:  \:  \sf CSA {(cylinder)} = 2 \times \dfrac{22}{7} \times 7 \times  10 \\  \\  \\  \dashrightarrow \:  \:  \sf CSA {(cylinder)}  = 2 \times 22 \times 10 \\  \\ \\   \dashrightarrow \:  \:  \sf CSA {(cylinder)} = 44 \times 10 \\  \\  \\  \dashrightarrow \:  \:  \sf CSA {(cylinder)}  = 440 \:  {cm}^{2}  \\ \\ \\

Now,

\dashrightarrow \:  \:  { \underline{ \boxed{ \pmb{ \sf{ \purple{Volume {(cylinder)}=  \pi {r}^{2} h}}}}}}  \:  \star \\  \\ \\

<em>Substituting the required values, </em>

\\

\dashrightarrow \:  \:   \sf Volume {(cylinder)}=  \dfrac{22}{7}  \times  {(7)}^{2}  \times 10 \\ \\  \\  \dashrightarrow \:  \:   \sf Volume {(cylinder)}=  \frac{22}{7}  \times 49  \times 10 \\ \\ \\  \dashrightarrow \:  \:   \sf Volume {(cylinder)}= 22 \times 7 \times 10 \\ \\  \\  \dashrightarrow \:  \:   \sf Volume {(cylinder)}= 1540 {cm}^{3}  \\ \\ \\

Hence,

  • CSA of the cylinder = 440 sq. cm

  • Volume of the cylinder = 1540 cu. cm
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Step-by-step explanation:


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