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const2013 [10]
3 years ago
9

If 50 empty soda cans weigh 3.5 pounds how much would 70 empty soda cans weigh ​

Mathematics
1 answer:
Basile [38]3 years ago
3 0
1000 pounds. First divide 50 by 3.5 to get the weight per soda can, then multiply your quotient by 70 and the product is 1000.
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Jamal and keisha went running keisha ran 2 miles more than jamal if keisha ran 8 miles how many miles did jamal run
kati45 [8]
Jamal would have run 10 miles
5 0
3 years ago
Which of the following correctly completes the square for the equation below?
erastova [34]
The answer is :

c. (x+1)²=20

To check:
(x+1)²=20                          (a+b)²=a²+2ab+b²
x²+2x+1=20
x²+2x=20-1
x²+2x=19
3 0
3 years ago
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About 2% of the population has a particular genetic mutation. 400 people are randomly selected. Find the mean for the number of
sergeinik [125]

Answer:

200

Step-by-step explanation:

So it'll be 400 ÷ 2 = 200 , and a way to to check your way would be 200 x 2 = 400

5 0
3 years ago
Find the partial fraction decomposition of the rational expression with prime quadratic factors in the denominator
SpyIntel [72]
\dfrac{5x^4-7x^3-12x^2+6x+21}{(x-3)(x^2-2)^2}=\dfrac{a_1}{x-3}+\dfrac{a_2x+a_3}{x^2-2}+\dfrac{a_4x+a_5}{(x^2-2)^2}
\implies 5x^4-7x^3-12x^2+6x+21=a_1(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(a_4x+a_5)(x-3)

When x=3, you're left with

147=49a_1\implies a_1=\dfrac{147}{49}=3

When x=\sqrt2 or x=-\sqrt2, you're left with

\begin{cases}17-8\sqrt2=(\sqrt2a_4+a_5)(\sqrt2-3)&\text{for }x=\sqrt2\\17+8\sqrt2=(-\sqrt2a_4+a_5)(-\sqrt2-3)\end{cases}\implies\begin{cases}-5+\sqrt2=\sqrt2a_4+a_5\\-5-\sqrt2=-\sqrt2a_4+a_5\end{cases}

Adding the two equations together gives -10=2a_5, or a_5=-5. Subtracting them gives 2\sqrt2=2\sqrt2a_4, a_4=1.

Now, you have

5x^4-7x^3-12x^2+6x+21=3(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(x-5)(x-3)
5x^4-7x^3-12x^2+6x+21=3x^4-11x^2-8x+27+(a_2x+a_3)(x-3)(x^2-2)
2x^4-7x^3-x^2+14x-6=(a_2x+a_3)(x-3)(x^2-2)

By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that a_2x^4=2x^4 and a_3(-3)(-2)=6a_3=-6. These alone tell you that you must have a_2=2 and a_3=-1.

So the partial fraction decomposition is

\dfrac3{x-3}+\dfrac{2x-1}{x^2-2}+\dfrac{x-5}{(x^2-2)^2}
7 0
3 years ago
Three moons are in the same circular orbit around a planet. The moons are each 115,000 kilometers from the surface of the planet
marshall27 [118]
275,000 km
The moons A, B, C form a right triangle with AC forming a hypotenuse with the diameter of the planet and the distance of both moons from the surface. So add A to the surface, plus the diameter of the planet, plus surface to c.
115000+45000+115000 = 275000
7 0
3 years ago
Read 2 more answers
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