<em>The answer is 58.</em>
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<em />
<em />
<em>First, we need to find</em><em> "x"</em><em>, being the </em><em>number.</em>
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- <em>13+45=58</em>
- <em>X=58</em>
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<h3><em>How did we get 58 though?</em></h3><h3><em /></h3><h3><em>----------Steps---------</em></h3>
- <em>Add</em><em> </em><em> 3+5</em>
- <em>3+5=8</em>
- <em>Then </em><em>add 1+4</em>
- <em>1+4=5</em>
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<em />
<em>Therefore, the answer is </em><em>58.</em>
<em>X=58</em>
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<em />
<em />
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<h3><em>Hope this heIps!</em></h3>
<em>If this helped...</em>
- <em>Give it a </em><em>good rating</em>
- <em>Give it a </em><em>thanks</em>
- <em>And maybe </em><em>brainliest!</em>
<h3><em>-------------------------------------------------</em></h3><h3><em>
~*This has been*~</em></h3>
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<em>#LearningWithBrainly</em>
We know that
Part a) <span>Find the fifth term of the arithmetic sequence in which t1 = 3 and tn = tn-1 + 4
t1=3
t2=t1+4----> 3+4-----> 7
t3=t2+4-----> 7+4----> 11
t4=t3+4-----> 11+4---> 15
t5=t4+4-----> 15+4---> 19
the answer Part a) is 19
Part b) </span><span>Find the tenth term of the arithmetic sequence in which t1 = 2 and t4 = -10
we know that
tn=t1+(n-1)*d-----> d=[tn-t1]/(n-1)
t1=2
t4=-10
n=4
find the value of d
d=[-10-2]/(4-1)-----> d=-12/3----> d=-4
find the </span>tenth term (t10)
t10=t1+(10-1)*(-4)----> t10=2+9*(-4)----> t10=-34
the answer Part b) is -34
Part c) <span>Find the fifth term of the geometric sequence in which t1 = 3 and tn = 2tn-1
t1=3
t2=2*t1----> 2*3----> 6
t3=2*t2----> 2*6----> 12
t4=2*t3-----> 2*12---> 24
t2=2*t4----> 2*24----> 48
the answer Part c) is 48</span>
Answer:
2x² + 4x + 3 = 0
Step-by-step explanation:
The function is said to be quadratic if it has highest degree = 2.
Further, The standard form of Quadratic Equation is:
ax² + bx + c = 0
where, a ≠ 0
a, b and c are constants
and x is unknown variable.
Thus, The Standard form of given Quadratic Equation is 2x² + 4x + 3 = 0
Answer: The answer is {(0,0)} !
Step-by-step explanation:
