Question

A gasoline tanker is filled with gasoline which weighs 45.93 lb/ft3. The dispensing valve at the base is jammed shut, forcing the operator to empty the tank via pumping the gas to a point 1 ft above the top of the tank. Assume the tank is a perfect cylinder, 20 ft long with a diameter of 7.5 ft. Set up the integral(s) that would allow you to find how much work is performed in pumping all the gasoline from the tank?

Answer 1

Answer:

The appropriate answer will be "Y = 157.09 N/m³".

Step-by-step explanation:

The given values are:

Diameter

= 7.5 ft

= 0.3048 meter

Height

= 20ft

= 6.096

Weight density

= 45.93 lb/ft³

= 16.0184634 kg/m³

Acceleration

= 9.807 m/s2

As we know,

The specified density of weight can be expressed as:

⇒  Specific weight = density × acceleration

i.e.,

⇒  $Y=\rho g$

On substituting the estimated values in the above expression, we get

⇒      $= 16.0184634\times 9.807$

⇒      $=157.09 \ N/m^3$