Ask question

Ask question

All categories

2 years ago

13

PLZZZZZ HELP MEEEEEEEEEEEEEEE

2 answers:

Inessa [10]2 years ago

6 0

The point at 0 x on the y axis the y-intercept, so -2

Eddi Din [679]2 years ago

4 0

Answer:

it is -1.

Step-by-step explanation:

its -1 because the y intercept is the straight vertical line, and you can see the dot is on it

You might be interested in

Find the inequality represented by the graph.

Korvikt [17]

Answer:

y>4x-2

Step-by-step explanation:

First let us find the equation of the line.

Given points (1,2) and (0, -2), the slope would be

(2-(-2))/(1-0) = 4/1= 4

The intercept is at -2, so the full equation would be

y=4x-2

However, we need to find the inequality of the graph. Everything greater than our line/above our line is included. Also notice that the line is dotted, which means that the line itself is not included.

Our equations should be,

y>4x-2

<em>I hope this helps! :)</em>

8 0

2 years ago

Find the mean of the data in the dot plot below.

NemiM [27]

Answer:

2.5 is the mean

3 0

2 years ago

Read 2 more answers

Find the Area of the figure below, composed of a rectangle and a semicircle. Round to the nearest tenths place.

luda_lava [24]

Answer:

286.97

Step-by-step explanation:

find the area of the rectangle first

14*15=210

Next

Find the area of a circle

πr^2=a

the radius of the circle is half the height of the rectangle

π*(7*7)=a

a=153.94

Now

Divide the area by two

153.94/2=76.97

Now add the two areas

76.97+210

7 0

2 years ago

Read 2 more answers

Expanded form for 41.32

Anna35 [415]

It is:

40+1+0.3+0.02=41.32

4 0

3 years ago

Read 2 more answers

g Use this to find the equation of the tangent line to the parabola y = 2 x 2 − 7 x + 6 at the point ( 4 , 10 ) . The equation o

natali 33 [55]

Answer:

The tangent line to the given curve at the given point is $y=9x-26$ .

Step-by-step explanation:

To find the slope of the tangent line we to compute the derivative of $y=2x^2-7x+6$ and then evaluate it for $x=4$ .

$(y=2x^2-7x+6)'$ Differentiate the equation.

$(y)'=(2x^2-7x+6)'$ Differentiate both sides.

$y'=(2x^2)'-(7x)'+(6)'$ Sum/Difference rule applied: $(f(x)\pmg(x))'=f'(x)\pm g'(x)$

$y'=2(x^2)'-7(x)'+(6)'$ Constant multiple rule applied: $(cf)'=c(f)'$

$y'2(2x)-7(1)+(6)'$ Applied power rule: $(x^n)'=nx^{n-1}$

$y'=4x-7+0$ Simplifying and apply constant rule: $(c)'=0$

$y'=4x-7$ Simplify.

Evaluate y' for x=4:

$y'=4(4)-7$

$y'=16-7$

$y'=9$ is the slope of the tangent line.

Point slope form of a line is:

$y-y_1=m(x-x_1)$

where $m$ is the slope and $(x_1,y_1)$ is a point on the line.

Insert 9 for $m$ and (4,10) for $(x_1,y_1)$ :

$y-10=9(x-4)$

The intended form is $y=mx+b$ which means we are going need to distribute and solve for $y$ .

Distribute:

$y-10=9x-36$

Add 10 on both sides:

$y=9x-26$

The tangent line to the given curve at the given point is $y=9x-26$ .

------------Formal Definition of Derivative----------------

The following limit will give us the derivative of the function $f(x)=2x^2-7x+6$ at $x=4$ (the slope of the tangent line at $x=4$ ):

$\lim_{x \rightarrow 4}\frac{f(x)-f(4)}{x-4}$

$\lim_{x \rightarrow 4}\frac{2x^2-7x+6-10}{x-4}$ We are given f(4)=10.

$\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}$

Let's see if we can factor the top so we can cancel a pair of common factors from top and bottom to get rid of the x-4 on bottom:

$2x^2-7x-4=(x-4)(2x+1)$

Let's check this with FOIL:

First: $x(2x)=2x^2$

Outer: $x(1)=x$

Inner: $(-4)(2x)=-8x$

Last: $-4(1)=-4$

---------------------------------Add!

$2x^2-7x-4$

So the numerator and the denominator do contain a common factor.

This means we have this so far in the simplifying of the above limit:

$\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}$

$\lim_{x \rightarrow 4}\frac{(x-4)(2x+1)}{x-4}$

$\lim_{x \rightarrow 4}(2x+1)$

Now we get to replace x with 4 since we have no division by 0 to worry about:

2(4)+1=8+1=9.

6 0

3 years ago