We first must find the value of angle z.
Angle z = 90° - 42°
Angle z = 48°
We now use the sine function to find y.
sin(48°) = 35/y
y = 35/sin(48°)
y = 47.0971455362
We now round off to two decimal places.
y = 47.10
I hope this helps....
It’s gonna be 5 units left and 4 units up. Because 5 is going negative in the x axis and 4 is going positive in the y axis
I think your asking how much the school will have left over. If so:
125 ( not including the tickets)
It depends on how many kids are coming to the dance in order to fully solve this problem.
You didn't word this properly so that what I got with what I had:)
If you have anymore questions, ask me them on my profile so I'll be sure to get them:)
I hope this helps:)
Answer:
Week=25 Hours
Weekend= 5 Hours
Step-by-step explanation:
So we need to use the info they gave us and create two equations. Firstly we know how much he gets paid per hour during the week (x) and how much he gets paid on the weekend (y).
$20x+$30y=$650
We get this because we know the combined rates he is paid times the hours should add up to the amount he earned.
The next equation will be made off of the information that he worked 5 times as many hours during the week as on the weekend. This tells us that we will take the weekend hours (y) and multiply them by 5 in order to get the week hours (x).
x=5y Now, since we have one variable by itself, we can plug it in for x in the first equation.
20(5y)+30y=650 Our first step here is to distribute the 20 to the 5y in order to eliminate the parenthesis.
100y+30y=650 Next add the like terms together (100y+30y).
Now all we have to do to find y is divide by 130 on both sides to get y alone.
130y=650
________
130 130
y=5 Now to solve for x we just plug our y value into one of the equations above. I'm going to use the second equation.
x=5(5)
x=25
9514 1404 393
Answer:
72°
Step-by-step explanation:
The external angle E is half the difference of subtended arcs CG and DF.
E = (CG -DF)/2
2E = CG -DF . . . . . . multiply by 2
DF = CG -2E = 160° -2(44°) . . . . . add DF-2E to both sides; substitute values
arc DF = 72°
