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balu736 [363]
3 years ago
9

Express the given quantity as a single logarithm and simplify: 3logx+2log(y-2)-5logx

Mathematics
1 answer:
storchak [24]3 years ago
3 0
Simplify each term<span>.</span>
Simplify <span>3log(x)</span><span> by moving </span>3<span> inside the </span>logarithm<span>. 
</span><span>log(<span>x^3</span>)+2log(y−1)−5log(x)</span><span> 
</span>
Simplify <span>2log(y−1)</span><span> by moving </span>2<span> inside the </span>logarithm<span>. 
</span><span>log(<span>x^3</span>)+log((y−1<span>)^2</span>)−5log(x)</span><span> 
</span>
Rewrite <span>(y−1<span>)^2</span></span><span> as </span><span><span>(y−1)(y−1)</span>.</span><span> 
</span><span>log(<span>x^3</span>)+log((y−1)(y−1))−5log(x)</span><span> 
</span>
Expand <span>(y−1)(y−1)</span><span> using the </span>FOIL<span> Method. 
</span><span>log(<span>x^3</span>)+log(y(y)+y(−1)−1(y)−1(−1))−5log(x)</span><span> 
</span>
Simplify each term<span>. 
</span><span>log(<span>x^3</span>)+log(<span>y^2</span>−2y+1)+log(<span>x^<span>−5</span></span>)</span><span> 

</span>Remove the negative exponent<span> by rewriting </span><span>x^<span>−5</span></span><span> as </span><span><span>1/<span>x^5</span></span>.</span><span> 
</span><span>log(<span>x^3</span>)+log(<span>y^2</span>−2y+1)+log(<span>1/<span>x^5</span></span>)</span><span> 
</span>
Combine<span> logs to get </span><span>log(<span>x^3</span>(<span>y^2</span>−2y+1))
</span><span>log(<span>x^3</span>(<span>y^2</span>−2y+1))+log(<span>1/<span>x^5</span></span>)

</span>Combine<span> logs to get </span><span>log(<span><span><span>x^3</span>(<span>y^2</span>−2y+1)/</span><span>x^5</span></span>)</span><span> 
</span>log(x^3(y^2−2y+1)/x^5)

Cancel <span>x^3</span><span> in the </span>numerator<span> and </span>denominator<span>. 
</span><span>log(<span><span><span>y^2</span>−2y+1/</span><span>x^2</span></span>)</span><span> 

</span>Rewrite 1<span> as </span><span><span>1^2</span>.</span> 
<span><span>y^2</span>−2y+<span>1^2/</span></span><span>x^2</span>

Factor<span> by </span>perfect square<span> rule. 
</span><span>(y−1<span>)^2/</span></span><span>x^2</span>

Replace into larger expression<span>. 
</span>
<span>log(<span><span>(y−1<span>)^2/</span></span><span>x^2</span></span>)</span> 
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jolli1 [7]

Answer:

20%

Step-by-step explanation:

im not really good at percentages but from what i know you first make it a fraction by adding all the numbers together to get 55(denominator). then for the numerator you take the section that they want(11). 11/55 is equal to 20/100(divide 100 by 55 and multiply the quotient by 11 to get 20). 20/100 is 20%. hope this kinda helps.

7 0
2 years ago
Evaluate the power: (−3)^4<br> A. 81<br> B. -81<br> C. 243<br> D. -331
Agata [3.3K]

Answer:

The answer is 81.

Step-by-step explanation:

Since the power of 4 is even, the result will be positive.

{3}^{4}

Simplify.

81

<u>hence</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>Option</u><u> </u><u>A</u><u>)</u><u> </u><u>81</u><u>.</u>

7 0
3 years ago
Read 2 more answers
At what point of the curve y = cosh(x does the tangent have slope 2?
Dahasolnce [82]
The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444

Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
5 0
3 years ago
-20y + 15 = 2 - 16y + 11
shtirl [24]
In order to answer this, we will first need to combine like terms on each side. on the left, you can leave them alone. however on the right, we will need to combine 2 and 11. this is 13. the right side becomes 13-16y. after that, we can add 20y to both sides. that equals 15=13+4y now we can subtract 13 from both sides. 2=4y. then we divide by 4 on both sides to find y. y=.5
7 0
3 years ago
Properties of 2-Dimensional Figures 1-7
Basile [38]

Answer:

1. PNT

2.RNM

3.QNM

4.UYZ

5. None

6.VYZ

7.none

Step-by-step explanation:

suplametery means when you add to angles together it will equal 180

while complementery is when to angels are added together to make 90 degrees

4 0
3 years ago
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