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balu736 [363]
3 years ago
9

Express the given quantity as a single logarithm and simplify: 3logx+2log(y-2)-5logx

Mathematics
1 answer:
storchak [24]3 years ago
3 0
Simplify each term<span>.</span>
Simplify <span>3log(x)</span><span> by moving </span>3<span> inside the </span>logarithm<span>. 
</span><span>log(<span>x^3</span>)+2log(y−1)−5log(x)</span><span> 
</span>
Simplify <span>2log(y−1)</span><span> by moving </span>2<span> inside the </span>logarithm<span>. 
</span><span>log(<span>x^3</span>)+log((y−1<span>)^2</span>)−5log(x)</span><span> 
</span>
Rewrite <span>(y−1<span>)^2</span></span><span> as </span><span><span>(y−1)(y−1)</span>.</span><span> 
</span><span>log(<span>x^3</span>)+log((y−1)(y−1))−5log(x)</span><span> 
</span>
Expand <span>(y−1)(y−1)</span><span> using the </span>FOIL<span> Method. 
</span><span>log(<span>x^3</span>)+log(y(y)+y(−1)−1(y)−1(−1))−5log(x)</span><span> 
</span>
Simplify each term<span>. 
</span><span>log(<span>x^3</span>)+log(<span>y^2</span>−2y+1)+log(<span>x^<span>−5</span></span>)</span><span> 

</span>Remove the negative exponent<span> by rewriting </span><span>x^<span>−5</span></span><span> as </span><span><span>1/<span>x^5</span></span>.</span><span> 
</span><span>log(<span>x^3</span>)+log(<span>y^2</span>−2y+1)+log(<span>1/<span>x^5</span></span>)</span><span> 
</span>
Combine<span> logs to get </span><span>log(<span>x^3</span>(<span>y^2</span>−2y+1))
</span><span>log(<span>x^3</span>(<span>y^2</span>−2y+1))+log(<span>1/<span>x^5</span></span>)

</span>Combine<span> logs to get </span><span>log(<span><span><span>x^3</span>(<span>y^2</span>−2y+1)/</span><span>x^5</span></span>)</span><span> 
</span>log(x^3(y^2−2y+1)/x^5)

Cancel <span>x^3</span><span> in the </span>numerator<span> and </span>denominator<span>. 
</span><span>log(<span><span><span>y^2</span>−2y+1/</span><span>x^2</span></span>)</span><span> 

</span>Rewrite 1<span> as </span><span><span>1^2</span>.</span> 
<span><span>y^2</span>−2y+<span>1^2/</span></span><span>x^2</span>

Factor<span> by </span>perfect square<span> rule. 
</span><span>(y−1<span>)^2/</span></span><span>x^2</span>

Replace into larger expression<span>. 
</span>
<span>log(<span><span>(y−1<span>)^2/</span></span><span>x^2</span></span>)</span> 
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What is the value of x if OB is<br> an angle bisector of
dangina [55]

Answer:

x = 8

Step-by-step explanation:

Hi there!

We're given that OB is the angle bisector of angle AOC.

An angle bisector splits an angle into 2 equal halves. Therefore, angles AOB and BOC are equal.

We're given that angle AOB is 8x degrees and angle BOC is 16x-64 degrees.

Set up an equation:

8x=16x-64

Combine like terms:

-8x=-64\\x=8

Therefore, x = 8.

I hope this helps!

4 0
3 years ago
What is a cubic polynomial function in standard form with zeros -4, -5, and 4?
hjlf
Hope it cleared your doubt.

7 0
4 years ago
I will give brainliest
ioda

Answer:

2,-5,-12,-19,-26

Step-by-step explanation:

-7n +9

-7(1) +9 = 2

-7(2)+ 9= -5

-7(3)+9 = -12

-7(4)+9 = -19

-7(5)+9 = -26

7 0
2 years ago
Three siblings date Kate and Sarah spent 100 hours helping Habitat for Humanity build new housing .Sarah worked 15 hours more th
Inessa [10]
The starting equation is
100=S+D+K
S is for Sarah, D is for Dave, and K is for Kate

This is what we know:
S=15+D
and
K=D-5
Now that we know how to find the values of everything, we must plug it in.

100=(15+D)+D+(D-5)
Combine like terms.
100=10+3D
Subtract 10 to isolate variable.
90=3D
Divide by 3 to isolate variable.
30=D
Plug in number to find the answers.

Answer:
Sarah worked for 45 hours
Dave worked for 30 hours
Kate worked for 25 hours
3 0
4 years ago
Read 2 more answers
Use the identity a^3+b^3=(a+b)^3−3ab(a+b) to determine the sum of the cubes of two numbers if the sum of the two numbers is 4 an
Butoxors [25]

a^3+b^3=(a+b)^3-3ab(a+b)\\\\a+b=4,\ ab=1\\\\\text{Substitute:}\\\\a^3+b^3=(4)^3-3(1)(4)=64-12=52

5 0
3 years ago
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