Given:

To find:
The value of f'(x).
Solution:
Formulae used:



Chain rule:
![\dfrac{d}{dx}[f(g(x))]=f'(g(x))g'(x)](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bdx%7D%5Bf%28g%28x%29%29%5D%3Df%27%28g%28x%29%29g%27%28x%29)
Where C is an arbitrary constant.
We have,

Differentiate with respect to x.


Therefore, the required values is
.
Answer:
![\left[\begin{array}{ccc}0&3&4\\0&7&-1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%263%264%5C%5C0%267%26-1%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
1.6+x-3.2=-2+5.6
simplify
-1.6+x=3.6
+1.6 both sides
x=5.2
Answer 4
The point is (3,4) for g(x)