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trasher [3.6K]
3 years ago
14

(x2-13x-48)÷(x+3) dividing polybomials

Mathematics
1 answer:
-BARSIC- [3]3 years ago
5 0
The final awser is x-16
hope this is what u needed
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What is the value of x in the figure?<br><br> A. 40<br> B. 70<br> C. 80<br> D. 120<br> E. 150
Marizza181 [45]

Answer:

E) 150°

Step-by-step explanation:

angle adjacent to 70° angle is 110°

the angle supplemental to 'x' must be 180-(40+110) or 30°

this means 'x' must be 150°

7 0
3 years ago
Read 2 more answers
What is the product of the polynomial? (5x^3 + 9x^2 + 6x + 1) ( x )
MAVERICK [17]

Answer:

5x^4+9x^3+6x^2+x

Step-by-step explanation:

hope that helped

4 0
4 years ago
28 (y - 1/7) = 28y - ?Rewrite, using the distributive property
Irina-Kira [14]

Given:

28(y-\frac{1}{7})=28y\text{ - ?}

To rewrite using distributive property, distribute the 28 to all values inside the parenthesis.

Thus, we have:

\begin{gathered} (28\ast y\text{ )-(28}\ast\frac{1}{7}) \\ =28y\text{ - 4} \end{gathered}

ANSWER:

28(y-\frac{1}{7})=28y\text{ - }4

28y - 4

4 0
1 year ago
Help please fast the format is Y-____=_____(x - ____) and i need the actual answer
mojhsa [17]

9514 1404 393

Answer:

  • y -195 = 15(x -9)
  • $60

Step-by-step explanation:

The form of the equation you are given is called "point-slope" form. The "slope" in this case is the per-hour fee. The point is (9 h, $195). Point-slope form generally looks like this:

  y -k = m(x -h) . . . . . line with slope m through point (h, k)

Here, you have m=15, (h, k) = (9, 195), so the equation looks like ...

  y -195 = 15(x -9)

__

The "one-time fee" is the cost when hours are zero.

  y -195 = 15(0 -9)

  y = 195 -9(15) = 60 . . . . add 195 to both sides, and evaluate

The one-time fee is $60.

5 0
3 years ago
As a single logarithm, 2log2 6- log29+ 1/3log2 27 = log2 12.
Ipatiy [6.2K]

Answer:

true

Step-by-step explanation:

2log2 6- log2 9+ 1/3log2 27 =

= log2 6² - log2 9 + log2 27^(1/3)

= log2 36 - log2 9 + log2 3

= log2 [(36 × 3)/9]

= log2 12

The statement is true.

3 0
2 years ago
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