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Virty [35]
3 years ago
13

Find the values of x and y

Mathematics
1 answer:
zhuklara [117]3 years ago
4 0

You can use a tangent:

tangent=\dfrac{opposite}{adjacent}

We have opposite = 17 and adjacent = x.

\tan30^o=\dfrac{\sqrt3}{3}

substitute:

\dfrac{17}{x}=\dfrac{\sqrt3}{3}       cross multiply

x\sqrt3=(3)(17)     multiply both sides by √3

x(\sqrt3)(\sqrt3)=51\sqrt3

3x=51\sqrt3      divide both sides by 3

x=17\sqrt3

Use the Pythagorean theorem:

y^2=(17\sqrt3)^2+17^2\\\\y^2=289(\sqrt3)^2+289\\\\y^2=289\cdot3+289\\\\y^2=867+289\\\\y^2=1156\to y=\sqrt{1156}\\\\y=34

-------------------------------------------------------------------------------------------------

Other method.

30^o-60^o-90^o triangle.

The sides are in the ratio 1:2:\sqrt3\to17:y:x

Therefore

17:(2\cdot17):(17\sqrt3)\to17:34:17\sqrt3\to x=34,\ y=17\sqrt3

 


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Answer:

0

Step-by-step explanation:

Imagine that you have zero cookies and you split them evenly among zero friends. How many cookies does each person get? See? It doesn't make sense. And Cookie Monster is sad that there are no cookies, and you are sad that you have no friends.

6 0
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bagirrra123 [75]

Answer:

Adding 1/4 each time

Step-by-step explanation:

1/4+1/4=1/2

1/2+1/4=3/4

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3 years ago
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liubo4ka [24]

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Step-by-step explanation:

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7 0
2 years ago
Find the common difference of the arithmetic sequence, the next three terms, the equation, and the term given for 8, 10, 12, 14
fredd [130]

Answer:

see explanation

Step-by-step explanation:

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d = a₂ - a₁ = 10 - 8 = 2

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a₅ = 14 + 2 = 16

a₆ = 16 + 2 = 18

a₇ = 18 + 2 = 20

The next 3 terms in the sequence are 16, 18, 20

The n th term equation for an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

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5 0
3 years ago
Solve the system and give your answer as a coordinate point in the form (k, c) k+c=100 51k+11c=2500
Aleks [24]

Answer:

k = 35, c = 65

Step-by-step explanation:

Solve the following system:

{c + k = 100 | (equation 1)

{11 c + 51 k = 2500 | (equation 2)

Swap equation 1 with equation 2:

{11 c + 51 k = 2500 | (equation 1)

{c + k = 100 | (equation 2)

Subtract 1/11 × (equation 1) from equation 2:

{11 c + 51 k = 2500 | (equation 1)

{0 c - (40 k)/11 = -1400/11 | (equation 2)

Multiply equation 2 by -11/40:

{11 c + 51 k = 2500 | (equation 1)

{0 c+k = 35 | (equation 2)

Subtract 51 × (equation 2) from equation 1:

{11 c+0 k = 715 | (equation 1)

{0 c+k = 35 | (equation 2)

Divide equation 1 by 11:

{c+0 k = 65 | (equation 1)

{0 c+k = 35 | (equation 2)

Collect results:

Answer: {c = 65 , k = 35

5 0
3 years ago
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