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Setler79 [48]
3 years ago
8

A conjecture and the flowchart proof used to prove the conjecture are shown.

Mathematics
2 answers:
dexar [7]3 years ago
8 0
Okay. An obtuse triangle is any triangle that has 1 angle that measures more than 90°. As we can see, angle QRS measures 76° and angle PRQ measures 104°. 104 > 90. Triangle PQR is a closed figure, and a triangle measures 180° total. There can only be 1 obtuse angle in any triangle. PRQ is an obtuse angle. Therefore, triangle PQR is an obtuse triangle.

Vsevolod [243]3 years ago
7 0

Answer:-

Given: m∠QRS=76°

Prove: △PQR is an obtuse triangle.

Proof:- ∠ORS=76° [given]

∠PRQ and ∠QRS are supplementary . [Linear pair postulate.]

m∠PRQ+76°=180° [Substitution property of equality]

m∠PRQ=104°  [Subtraction property of equality]

∠PRQ is an obtuse angle [Definition of obtuse angle]

ΔPQR is an obtuse triangle.[Definition of obtuse triangle]


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A​ bank's loan officer rates applicants for credit. The ratings are normally distributed with a mean of 200 and a standard devia
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Answer:

Upper P60 = 212.8

Step-by-step explanation:

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In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 200, \sigma = 50

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This is the value of X when Z has a pvalue of 0.6. So it is X when Z = 0.255.

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0.255 = \frac{X - 200}{50}

X - 200 = 0.255*50

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8 0
4 years ago
These tables represent a quadratic function with a vertex at (0,3). What is the average rate of change for the interval from X =
Eva8 [605]

Answer:

-19

Step-by-step explanation:

The missing table is shown in the attachment.

Since the quadratic function has vertex at (0,3), its equation is of the form;

y = a {x}^{2}  + 3

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2 = a( {1)}^{2}  + 3

a = 2 - 3 =  - 1

Hence the function is

y =  -  {x}^{2} +  3

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f(9) =  - 81 + 3 =  - 78

The average rate of change from x=9 to x=10 is

\frac{f(10) - f(9)}{10 - 9}  =  \frac{ - 97 -  - 78}{1}  =   - 19

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4 years ago
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