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IgorLugansk [536]
3 years ago
9

How to classify a polynomial by its degree​

Mathematics
1 answer:
Andreas93 [3]3 years ago
8 0

Answer:Classifying Polynomials. Polynomials can be classified two different ways - by the number of terms and by their degree. A monomial has just one term. For example, 4x2 .Remember that a term contains both the variable(s) and its coefficient (the number in front of it.)

Step-by-step explanation:Hope this helps. Please name me brainliest

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Explain how you find it
aliina [53]

Answer:

x = 39

Step-by-step explanation:

there is a theorem that states that the midsegment in a trapezoid is equal to the sum of the bases divided by two

so, (36 + 42)/2 = x

36 + 42 = 78

78/2 = 39

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X/2 - y/3 = 3/2<br>X/3 + y/2 = 16/3
Ivenika [448]
X/2-y/3=3/2
(6×x/2)-(6×y/3)=6×3/2
3x-2y=9______(1)

x/3+y/2=16/3
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y=6
4 0
3 years ago
James has a square piece of paper he wants to cut it into 20 strips of equal with he says this piece of paper is about 48 centim
madam [21]
28 width each strip centimeters
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Encuentra la ecuacion de la parabola con vertice en el origen y foco en las cordenadas 0,1en su forma ordinaria y general
marusya05 [52]

Answer:

x^{2}=4y

y=\frac{1}{4}x^{2}

Step-by-step explanation:

Forma ordinaria

La ecuación de la parabola de manera ordinaria está dada por:

(x-h)^{2}=4p(y-k) (1)  

Donde:

  • (h,k) es la coordenda del vértice, en nuestro caso (0,0) ya que está en el origen.
  • (h,k+p) es la coordenda del foco, en nuestro caso (0,1).

Por lo tanto h = 0, k = 0 y p = 1.

Remplazando estos valores en la ecuación de la parábola, tenemos:

(x-0)^{2}=4*1(y-0)

x^{2}=4y (2)

 

Forma general  

La forma general de una parábola esta dada por la siquiente ecuación

y=ax^{2}+bx+c

Reordenando la ecuación (2) tenemos:

y=\frac{1}{4}x^{2}

Espero esto te haya ayudado!

5 0
3 years ago
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