Answer : (8,5)
Given
K(x) = ![8-\sqrt[3]{x}](https://tex.z-dn.net/?f=8-%5Csqrt%5B3%5D%7Bx%7D)
Now we plug in each point and check whether it satisfies our equation
(-64,12)
K(-64) = ![8-\sqrt[3]{-64}](https://tex.z-dn.net/?f=8-%5Csqrt%5B3%5D%7B-64%7D)
= 12 so this point lie on graph
(125,3)
K(125) = ![8-\sqrt[3]{125}](https://tex.z-dn.net/?f=8-%5Csqrt%5B3%5D%7B125%7D)
= 3 so this point lie on graph
(343,1)
K(343) = ![8-\sqrt[3]{343}](https://tex.z-dn.net/?f=8-%5Csqrt%5B3%5D%7B343%7D)
= 1 so this point lie on graph
(8,5)
K(8) = ![8-\sqrt[3]{8}](https://tex.z-dn.net/?f=8-%5Csqrt%5B3%5D%7B8%7D)
= 6 so this point does not lie on graph because we got 6 instead of 5
Answer:A 16-ounce can of mixed nuts includes 6 ounces of cashews and 10 ounces of almonds. What is the ratio of almonds to mixed nuts in this can of nuts?
Step-by-step explanation:
Answer: the dog eats 68.76 lbs of food in 18 weeks
Step-by-step explanation: 3.82x 18=68.76
Answer:
1. the range of f^-1(x) is {10, 20, 30}.
2. the graph of f^-1(x) will include the point (0, 3)
3. n = 8
Step-by-step explanation:
1. The domain of a function is the range of its inverse, and vice versa. The range of f^-1(x) is {10, 20, 30}.
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2. See above. The domain and range are swapped between a function and its inverse. That means function point (3, 0) will correspond to inverse function point (0, 3).
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3. The n-th term of an arithmetic sequence is given by ...
an = a1 +d(n -1)
You are given a1 = 2, a12 = 211, so ...
211 = 2 + d(12 -1)
209/11 = d = 19 . . . . . solve the above equation for the common difference
Now, we can use the same equation to find n for an = 135.
135 = 2 + 19(n -1)
133/19 = n -1 . . . . . . . subtract 2, divide by 19
7 +1 = n = 8 . . . . . . . . add 1
135 is the 8th term of the sequence.
Hello :
the <span>coordinates </span> circumcenter for ∆DEF :
x = (1+7+1)/3
y = (1+1+5//3
x=3
y= 7/3
