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kupik [55]
3 years ago
8

If the line x = 3 is the axis of symmetry of a parabola, which coordinates below could be x-intercepts of the parabola?

Mathematics
1 answer:
guapka [62]3 years ago
8 0

Answer:

(-1,0) and (5,0)

Step-by-step explanation:

You might be interested in
Please help me find x
Ghella [55]

Answer:

x = 53

Step-by-step explanation:

Remember that the sum of all 3 interior angles in a triangle is 180∘ so

74 + x + x = 180

74 + 2x = 180

2x = 180 - 74

2x = 106

x = 106/2

x = 53

3 0
3 years ago
Read 2 more answers
3. (02.01)
sashaice [31]

Answer:

A. 1

Step-by-step explanation:

3(x+1)=-2(x-1)+6

3x+3=2x-2+6

x+3=4

x=1

7 0
3 years ago
A skier has decided that on each trip down a slope, she will do 3 more jumps than before. On her first trip she did 5 jumps. Der
taurus [48]
Since we are already given the amount of jumps from the first trial, and how much it should be increased by on each succeeding trial, we can already solve for the amount of jumps from the first through tenth trials. Starting from 5 and adding 3 each time, we get: 5 8 (11) 14 17 20 23 26 29 32, with 11 being the third trial.

Having been provided 2 different sigma notations, which I assume are choices to the question, we can substitute the initial value to see if it does match the result of the 3rd trial which we obtained by manual adding.

Let us try it below:

Sigma notation 1:

  10
<span>   Σ (2i + 3)
</span>i = 3

@ i = 3

2(3) + 3
12

The first sigma notation does not have the same result, so we move on to the next.

  10
<span>   Σ (3i + 2)
</span><span>i = 3
</span>
When i = 3; <span>3(3) + 2 = 11. (OK)
</span>
Since the 3rd trial is a match, we test it with the other values for the 4th through 10th trials.

When i = 4; <span>3(4) + 2 = 14. (OK)
</span>When i = 5; <span>3(5) + 2 = 17. (OK)
</span>When i = 6; <span>3(6) + 2 = 20. (OK)
</span>When i = 7; 3(7) + 2 = 23. (OK)
When i = 8; <span>3(8) + 2 = 26. (OK)
</span>When i = 9; <span>3(9) + 2 = 29. (OK)
</span>When i = 10; <span>3(10) + 2 = 32. (OK)

Adding the results from her 3rd through 10th trials: </span><span>11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 172.
</span>
Therefore, the total jumps she had made from her third to tenth trips is 172.


3 0
3 years ago
Can Someone help me answer these?
Fittoniya [83]

for number 15

K= 12

for 17

answer is -36

4 0
3 years ago
Read 2 more answers
Find the area of this parallelogram 13cm 15cm 20cm
Georgia [21]

Answer:

260cm²

Step-by-step explanation:

area of this parallelogram 20×13=260cm²

4 0
2 years ago
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