Answer:
a) 17.09 hours
b) The 95% confidence interval estimate of the population mean flying time for the Pilots is between 31.91 hours and 66.09 hours
Step-by-step explanation:
We have the standard deviation of the sample, so we use the t distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 49 - 1 = 48
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 48 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 2.0106
The margin of error is:
M = T*s = 2.0106*8.5 = 17.09
s is the standard deviation of the sample. 17.09 hours is the answer for a.
The lower end of the interval is the sample mean subtracted by M. So it is 49 - 17.09 = 31.91 hours
The upper end of the interval is the sample mean added to M. So it is 49 + 17.09 = 66.09 hours
The 95% confidence interval estimate of the population mean flying time for the Pilots is between 31.91 hours and 66.09 hours
One of two things:
-There is no solution because they are parallel lines
- OR There is infinite solutions because they are the same line.
Step-by-step explanation:
the average rate of change between two input values is the total change of the function values (output values) divided by the change in the input values.
so,
(h(7) - (h(3)) / (7 - 3)
h(7) = 7² - 7×7 + 6 = 49 - 49 + 6 = 6
h(3) = 3² - 7×3 + 6 = 9 - 21 + 6 = -6
7 - 3 = 4
(6 - -6)/4 = 12/4 = 3
the average change rate in that interval is 3 (or fully 3/1).
Answer:
40 minutes.
Step-by-step explanation:
- time spent on the thread mill as a function of d(day) = t(d)
= 30 +2(d-1) minutes
[where d represents day number]
(when d is 1 the time spent should be 30
so substitute d=1 and check it will be 30 only.
on first day he will spend 30 minutes so, I added 30 .
and on every additional day( these additional days are excluding first day), he will increase the time by 2 minutes.so, I added 2(d-1) to initial 30 minutes)
- so, T(6), the minutes he will spend on the treadmill on day 6=
=30+2(6-1)
=30+2(5)
=30+10
=40 minutes
