Question

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Answer 1

Answer:

After 1.5 second of throwing the ball will reach a maximum height of 44 ft.

Step-by-step explanation:

The height in feet of a ball after t seconds of throwing is given by the function  

h = - 16t² + 48t + 8 .......... (1)

Now, condition for maximum height is  

$\frac{dh}{dt} = 0 = - 32t + 48$ {Differentiating equation (1) with respect to t}

⇒ $t = \frac{48}{32} = 1.5$ seconds.

Now, from equation (1) we get

h(max) = - 16(1.5)² + 48(1.5) + 8 = 44 ft.

Therefore, after 1.5 seconds of throwing the ball will reach a maximum height of 44 ft. (Answer)