Plz help plzzzzzzzzzzzz

Mathematics

1 answer:

saveliy_v [14]3 years ago

4 0

Answer:

After 1.5 second of throwing the ball will reach a maximum height of 44 ft.

Step-by-step explanation:

The height in feet of a ball after t seconds of throwing is given by the function

h = - 16t² + 48t + 8 .......... (1)

Now, condition for maximum height is

$\frac{dh}{dt} = 0 = - 32t + 48$ {Differentiating equation (1) with respect to t}

⇒ $t = \frac{48}{32} = 1.5$ seconds.

Now, from equation (1) we get

h(max) = - 16(1.5)² + 48(1.5) + 8 = 44 ft.

Therefore, after 1.5 seconds of throwing the ball will reach a maximum height of 44 ft. (Answer)

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calculate 4.5 times 10^negative 2 divided by 8.3 times 10^negative 4 by using scientific notation and the product rule. round an

Degger [83]

Answer:

5.4217 • 10¹

Step-by-step explanation:

4.5 • 10⁻² ÷ 8.3 • 10⁻⁴

450 ÷ 8.3

54.21686...

54.217

5.4217 • 10¹

I hope this helps

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3 years ago

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3 years ago

K=mv^2/2 solve for v

matrenka [14]

Answer: $v=\sqrt[]{\frac{2K}{m} }$

Step-by-step explanation:

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First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;

$2*K=\frac{mv^2}{2}*2$