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3 years ago

PLEASE PLEASE HELP !!

Mathematics

1 answer:

Virty [35]3 years ago

6 0

Answer:

∠G = 23.3

∠H = 42.8

∠J = 19.9

Step-by-step explanation:

Tan(G) = 0.43

=> G = Tan⁻¹(0.43)

=> ∠G = 23.3

Sin(H) = 0.68

=> H = Sin⁻¹(0.68)

=> ∠H = 42.8

Cos(J) = 0.94 

=> J = Cos⁻¹(0.94)

=> ∠J = 19.9

Hope this helps!

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Write 460,000,000 as a power of ten.

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Determine the slope of each line segment of AQRS. Show your work or explain your reasoning.

ElenaW [278]

The slope of each line segment of ΔQRS are-

QR = 3/10
RS = - 10/3
QS = -7/13

<h3>What is meant by the slope of the line?</h3>

A slope of a line is defined in mathematics as the change in y coordinate to regard to the shift in x coordinate.
The net change in y-coordinate is denoted by Δy, whereas the net change in x-coordinate is denoted by Δx.

For the given question,

The coordinates of each vertices of the triangle are-

Q = (-7, -2)

R = (3, 1)

S = (6, -9)

The formula for the slope of the line segment.

Slope = m = (y2 - y1)/(x2 - x1)

Slope QR = (1 + 2)/(3 + 7)

Slope QR = 3/10

Slope RS = (-9 - 1)/(6 - 3)

Slope RS = - 10/3

Slope QS = (-9 + 2)/(6 + 7)

Slope QS = -7/13

Thus, the slope of the each line segment of the given triangle QRS is found.

To know more about the slope of the line, here

brainly.com/question/16949303

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1 year ago

A. one solution B. infinitely many solutions C. no solution

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It should be A-one solution

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2 years ago

Solve this equation. 25) v - 6(4v + 6) = -82

grin007 [14]

Answer:

$v = 2$

Step-by-step explanation:

Hi there! I'm glad I was able to help you solve this equation!

Let's start by simplifying both sides of the equation. It's easier to solve it this way!

$v - 6 (4v + 6) = -82$

Distribute:

$v + (-6) (4v) + (-6) (6) = -82$

$v + -24v + -36 = -82$

Combine 'like' terms:

$(v -24v) + (-36) = -82$

$-23v - 36 = -82$

Next, you'll want to add 36 to both sides of the equation.

$-23v-36 + 36 = -82 + 36$

$-23v = -46$

Finally, divide both sides by $-23$ .

$\frac{-23v}{-23} = \frac{-46}{-23}$

$v = 2$

I hope this helped you! Leave a comment below if you have any further questions! :)

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3 years ago