Answer:
Step-by-step explanation:
-10+sqrt2x+1 = -5
sqrt2x+1 = -5+10
sqrt2x+1 = 5
2x+1 = sqrt5
2x = sqrt5-1
x = (sqrt5-1)/2
<h2>Question:</h2>
What word below best describes this quadrilateral?
<h2>Answer:</h2>
<u>B</u><u>.</u><u> </u><u>Parallelogram</u><u> </u>
<h3>
<u>#CARRYONLEARNING</u><u> </u></h3><h3>
<u>#STUDYWELL</u><u> </u></h3>
Here, Let coordinates = ( 0, y)
Let, y-axis divides line in the ratio = k : 1
Now, (0, y) = [(10k-4) / k+1 , (12k-6)/ k + 1 ]
0 = 10k - 4 / k+1
10k = 4
k = 4/10 = 2/5
In short, Your ratio of division would be: 2 : 5
Now, y = (12k - 6)/ k + 1
y = 12*2/5 - 6 / 2/5 + 1
y = -6/7
In short, Your Coordinates would be: (0, -6/7 )
Hope this helps!
Answer:
6 hours
Step-by-step explanation:
We can think of this problem as a "work" problem and use the formula:
work = rate x time
Let p be the rate of a single pump. So the total rate of 3 pumps is 3p. And the total time is 8 hours, so the work needed to fill a pool is:
work = 3p x 8 = 24p
We need 24p to fill up a pool.
So what happens when you have 4 pumps? That is a rate of 4p. So how much time is needed to fill up a pool that requires 24p of work?
Solve by using the work = rate x time equation:
24p = 4p x t
6 = t
6 hours.
36 + x = 2(11 + x)
36+x=22+2x
14=x
John will be twice Jimmy's age in 14 years.
Alternate way:
Keep writing their ages for every year until John is twice Jimmy's age.
In the beginning: John is 36 years old, Jimmy is 11 years old.
As the years pass...
After 1 years: (John, 37), (Jimmy, 12)
After 2 years: (John, 38), (Jimmy, 13)
After 3 years: (John, 39), (Jimmy, 14)
After 4 years: (John, 40), (Jimmy, 15)
After 5 years: (John, 41), (Jimmy, 16)
After 6 years: (John, 42), (Jimmy, 17)
After 7 years: (John, 43), (Jimmy, 18)
After 8 years: (John, 44), (Jimmy, 19)
After 9 years: (John, 45), (Jimmy, 20)
After 10 years: (John, 46), (Jimmy, 21)
After 11 years: (John, 47), (Jimmy, 22)
After 12 years: (John, 48), (Jimmy, 23)
After 13 years: (John, 49), (Jimmy, 24)
After 14 years: (John, 50), (Jimmy, 25)
