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3 years ago

Find the radical equivalent of 272/3 and compute it?

2 answers:

4 0

From my research, the question is actually looking for the radical equivalent of 27^(2/3). Let us solve this below:

27^(2/3) = [cube root (27)]^2 = 3^2 = 9

Therefore, the final answer to the expression is 9.

frez [133]3 years ago

4 0

Answer: The radical equivalent of $27^{\frac{2}{3}}\\$ is 9.

Step-by-step explanation:

Since we have given that

$27^{\frac{2}{3}}\\$

We need to find the radical equivalent.

so, we will use the "Exponential law":

$(a^m)^{\frac{1}{n}}=a^{\frac{m}{n}}$

so, it becomes,

$27^\frac{2}{3}\\\\=(3^3)^\frac{2}{3}\\\\=(3^\frac{3}{3})^2\\\\=3^2\\\\=9$

Hence, The radical equivalent of $27^{\frac{2}{3}}\\$ is 9.

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A ladder 20 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2

alukav5142 [94]

Answer:

0.17 °/s

Step-by-step explanation:

Since the ladder is leaning against the wall and has a length, L and is at a distance, D from the wall. If θ is the angle between the ladder and the wall, then sinθ = D/L.

We differentiate the above expression with respect to time to have

dsinθ/dt = d(D/L)/dt

cosθdθ/dt = (1/L)dD/dt

dθ/dt = (1/Lcosθ)dD/dt where dD/dt = rate at which the ladder is being pulled away from the wall = 2 ft/s and dθ/dt = rate at which angle between wall and ladder is increasing.

We now find dθ/dt when D = 16 ft, dD/dt = + 2 ft/s, and L = 20 ft

We know from trigonometric ratios, sin²θ + cos²θ = 1. So, cosθ = √(1 - sin²θ) = √[1 - (D/L)²]

dθ/dt = (1/Lcosθ)dD/dt

dθ/dt = (1/L√[1 - (D/L)²])dD/dt

dθ/dt = (1/√[L² - D²])dD/dt

Substituting the values of the variables, we have

dθ/dt = (1/√[20² - 16²]) 2 ft/s

dθ/dt = (1/√[400 - 256]) 2 ft/s

dθ/dt = (1/√144) 2 ft/s

dθ/dt = (1/12) 2 ft/s

dθ/dt = 1/6 °/s

dθ/dt = 0.17 °/s

8 0

3 years ago

Help once more please

REY [17]

Answer:

Step-by-step explanation:

they are all equal sides so what you'd do is 28+28+28= 84

5 0

3 years ago

Read 2 more answers

The vertex angle of an isosceles triangle measures 64 degrees. What is the measure of its base angles?

Dvinal [7]

So hmmm check the picture below

in an isosceles triangle, two sides are equal, and thus the angles those twin legs make, are also twin angles

let's say the angle made is "a", so all internal angles will be 64 + a + a = 180
or 64 + 2a = 180

thus 2a = 180 - 64 => 2a = 116, thus a = 116/2