Ask question

Ask question

All categories

3 years ago

15

3. The directions on a seed packet say to plant the seeds 1 inches

1 answer:

Tatiana [17]3 years ago

7 0

One inch is a whole number so the decimal equivalent for it would just be 1.0 inches. If you have to convert it into cm it would be 2.54cm. But Could you elaborate if something is missing

You might be interested in

Consider the matrix A. A = 1 0 1 1 0 0 0 0 0 Find the characteristic polynomial for the matrix A. (Write your answer in terms of

dusya [7]

Answer with Step-by-step explanation:

We are given that a matrix

$A=\left[\begin{array}{ccc}1&0&1\\1&0&0\\0&0&0\end{array}\right]$

a.We have to find characteristic polynomial in terms of A

We know that characteristic equation of given matrix $\mid{A-\lambda I}\mid=0$

Where I is identity matrix of the order of given matrix

I= $\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]$

Substitute the values then, we get

$\begin{vmatrix}1-\lambda&0&1\\1&-\lambda&0\\0&0&-\lambda\end{vmatrix}=0$

$(1-\lambda)(\lamda^2)-0+0=0$

$\lambda^2-\lambda^3=0$

$\lambda^3-\lambda^2=0$

Hence, characteristic polynomial = $\lambda^3-\lambda^2=0$

b.We have to find the eigen value for given matrix

$\lambda^2(1-\lambda)=0$

Then , we get $\lambda=0,0,1-\lambda=0$

$\lambda=1$

Hence, real eigen values of for the matrix are 0,0 and 1.

c.Eigen space corresponding to eigen value 1 is the null space of matrix $A-I$

$E_1=N(A-I)$

$A-I=\left[\begin{array}{ccc}0&0&1\\1&-1&0\\0&0&-1\end{array}\right]$

Apply $R_1\rightarrow R_1+R_3$

$A-I=\left[\begin{array}{ccc}0&0&1\\1&-1&0\\0&0&0\end{array}\right]$

Now,(A-I)x=0[/tex]

Substitute the values then we get

$\left[\begin{array}{ccc}0&0&1\\1&-1&0\\0&0&0\end{array}\right]\left[\begin{array}{ccc}x_1\\x_2\\x_3\end{array}\right]=0$

Then , we get $x_3=0$

And $x_1-x_2=0$

$x_1=x_2$

Null space N(A-I) consist of vectors

x= $\left[\begin{array}{ccc}x_1\\x_1\\0\end{array}\right]$

For any scalar $x_1$

$x=x_1\left[\begin{array}{ccc}1\\1\\0\end{array}\right]$

$E_1=N(A-I)=Span(\left[\begin{array}{ccc}1\\1\\0\end{array}\right]$

Hence, the basis of eigen vector corresponding to eigen value 1 is given by

$\left[\begin{array}{ccc}1\\1\\0\end{array}\right]$

Eigen space corresponding to 0 eigen value

$N(A-0I)=\left[\begin{array}{ccc}1&0&1\\1&0&0\\0&0&0\end{array}\right]$

$(A-0I)x=0$

$\left[\begin{array}{ccc}1&0&1\\1&0&0\\0&0&0\end{array}\right]\left[\begin{array}{ccc}x_1\\x_2\\x_3\end{array}\right]=0$

$\left[\begin{array}{ccc}x_1+x_3\\x_1\\0\end{array}\right]=0$

Then, $x_1+x_3=0$

$x_1=0$

Substitute $x_1=0$

Then, we get $x_3=0$

Therefore, the null space consist of vectors

$x=x_2=x_2\left[\begin{array}{ccc}0\\1\\0\end{array}\right]$

Therefore, the basis of eigen space corresponding to eigen value 0 is given by

$\left[\begin{array}{ccc}0\\1\\0\end{array}\right]$

5 0

3 years ago

Simplify the expression<br>a²+a+a²

sasho [114]

Answer:

2a^2+a

Step-by-step explanation:

you can simplify a^2 into itself twice

7 0

3 years ago

The total of 26, 78, 198, 475 and 620 is

MissTica

The answer is 1,397

26+78+198+475+620=1,397

8 0

4 years ago

Read 2 more answers

At a country concert, the ratio of the number of boys to the number of girls is 2:7. If there are 250 more girls than boys, how

zvonat [6]

Boys : Girls = 2:7
let the no. of boys be x
so no of girls = 250+x
so, x:(250+x) = 2:7
x/(250+x) = 2/7
7x = 500+2x
7x-2x = 500
x = 500/5 =100

8 0

3 years ago

5x + 4m = 43my + 6 solve for m

pav-90 [236]

9514 1404 393

Answer:

m = (5x -6)/(43y -4)

Step-by-step explanation:

Subtract 4m+6 to separate m-terms from other terms.

5x +4m -(4m +6) = 43my +6 -(4m +6)

5x -6 = 43my -4m

5x -6 = m(43y -4) . . . . factor out m

(5x -6)/(43y -4) = m . . . . divide by the coefficient of m

7 0

3 years ago