Answer:
Just factorize the given plynomials.
Step-by-step explanation:
like in first example 7x+49
7(x+7)
Answer: there were 692 visitors on Saturday.
Step-by-step explanation:
Let x represent the number of visitors that were there on Friday.
Let y represent the number of visitors that were there on Saturday.
Let z represent the number of visitors that were there on Sunday.
The theme park had 1099 visitors in 3 days. It means that
x + y + z = 1099- - - - - - - - - - - - - -1
There were twice as many visitors on saturday than on Friday. This means that
y = 2x
x = y/2
There were 234 more visitors on Sunday than on Saturday. This means that
z = y + 234
Substituting x = y/2 and z = y + 234 into equation 1, it becomes
y/2 + y + y + 234 = 1099
Cross multiplying by 2, it becomes
y + 2y + 2y + 468 = 2198
5y = 2198 - 468
5y = 1730
x = 1730/5
x = 346
y = 2x = 2 × 346
y = 692
z = y + 234 = 692 + 234
z = 926
Hello,
Use the factoration
a^2 - b^2 = (a - b)(a + b)
Then,
x^2 - 81 = x^2 - 9^2
x^2 - 9^2 = ( x - 9).(x + 9)
Then,
Lim (x^2- 81) /(x+9)
= Lim (x -9)(x+9)/(x+9)
Simplity x + 9
Lim (x -9)
Now replace x = -9
Lim ( -9 -9)
Lim -18 = -18
_______________
The second method without using factorization would be to calculate the limit by the hospital rule.
Lim f(x)/g(x) = lim f(x)'/g(x)'
Where,
f(x)' and g(x)' are the derivates.
Let f(x) = x^2 -81
f(x)' = 2x + 0
f(x)' = 2x
Let g(x) = x +9
g(x)' = 1 + 0
g(x)' = 1
Then the Lim stay:
Lim (x^2 -81)/(x+9) = Lim 2x /1
Now replace x = -9
Lim 2×-9 = Lim -18
= -18
Now that we’ve learned how to solve word problems involving the sum of consecutive integers, let’s narrow it down and this time, focus on word problems that only involve finding the sum of consecutive even integers.
But before we start delving into word problems, it’s important that we have a good understanding of what even integers, as well as consecutive even integers, are.
Even Integers
We know that even numbers are integers that can be divided exactly or evenly by 22. Thus, the general form of the even integer nn, is n = 2kn=2k, where kk is also an integer.
In other words, since even numbers are the multiples of 22, we can represent an even integer nn by 2k2k, where kk is also an integer. So if we have the even integers 1010 and 1616,
3500(1 + .03/12)^12(5)
3500(1.0025)^60
The answer is:
$4,065.66 or $4,066
Hope this helps :)
