Select all that apply.
2 answers:
The correct answer to the question is B) watt and D) joule/sec.
EXPLANATION:
As per the question, the physical quantity given is power.
The power is defined as the rate of consumption of energy or the rate of doing work.
Let us consider W is the amount of work done by a body in time t .
Mathematically the power of that body is written as -
power p =
The unit of work is joule and the unit of time is second.
Hence, the unit of power is joule/sec.
we know that one joule/sec. = one watt.
Hence, watt is also another unit of power.
newton-metre can not be a unit of power . It may be considered as a unit of work.
Similarly H.P/sec is also not a unit of power. Here H.P stands for horse power which is another unit of power .
Hence, joule/sec. and watt are the appropriate units of power.
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To solve this problem we will begin by finding the force on each of the elements. For this it will be necessary to obtain the mass, which can be related to density and volume. Finally, by balancing forces it will be possible to obtain the final value of the maximum mass that can be lifted.
By Newton's second law we have,
Here,
g = Gravitational acceleration
m = mass
At the same time mass can be described as,
Therefore the Force 1 is,
Applying the same concepto but for the second mass we have,
Now by equilibrium we have,
Therefore the maximum mass lift by balloon is
Answer:
See the explanation below.
Explanation:
We have to take into account that the potential difference is equal to the voltage, and this is measured between two points as the resistors are connected in parallel to the voltage source, the resistors will have the same voltage.
For ease, we will take the attached image of resistors connected in parallel.
As both resistors at their ends share the A & B connection points, these are at a voltage of 12V
