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otez555 [7]
3 years ago
9

Work out m and c for the line: y = 8 x

Mathematics
1 answer:
Ivan3 years ago
8 0

Answer:

m = 8 and c = 0

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 8x ← is in slope- intercept form, that is y = 8x + 0

with m = 8 and c = 0

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How many solutions does the equation m1x + b1 = m2x + b2 have? Explain.
harina [27]

Answer:

No-Solution

Step-by-step explanation:

On a graph the lines do not meet; they are parallel lines

3 0
4 years ago
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Please help worth 25 points
wariber [46]

Answer:

h=6 feet

Step-by-step explanation:

Given: 1. The base of a rectangle is three feet longer than its height.

2.Are of the rectangle=54 square meters

Let us say the rectangle has height h and base(breadth) b.

Since, the base of the rectangle is three feet longer than the height, we have b=h+3.

Also, Area of the Rectangle= hb

therefore, 54=h(h+3)

54= h2+ 3h

h2+3h-54=0 (Subtract 54 from both the sides)

To find the value of h we have to solve the quadratic equation.

[We have the equation in the form ax2+bx+c=0, to factorise the equation-

Step1. Find two numbers such that their multiplication is equal to ac and their addition is equal to b.

Step2. Replace b with these numbers.

Step3. Simplify the equation]

So, h2+3h-54=0

h2+9h-6h-54=0

h(h+9)-6(h+9)=0

(h+9)(h-6)=0

Which gives-

h= -9 or h= 6

As h is the height of the rectangle, h can not be -9.

so h=6 feet

and b=h+3=9 feet

So the dimensions of the rectangle are 6 feet for the height and 9 feet for the base.

5 0
3 years ago
Find domain of y=rad20-6x
Evgesh-ka [11]
Domain, on an "even root" context, means, an even root cannot have a negative radicand, since  say for example \bf \sqrt{-25}\ne -5\qquad why?\implies (-5)(-5)=25

so... you end up with an "imaginary value"

so... for the case of 20-6x
"x", the domain, or INPUT
can afford to have any value, so long it doesn't make the radicand negative

to check for that, let us make the expression to 0, and see what is "x" then

\bf 20-6x=0\implies 20=6x\implies \cfrac{20}{6}=x\implies \cfrac{10}{3}=x

now, if "x" is 10/3, let's see \bf \sqrt{20-6\left( \frac{10}{3} \right)}\implies \sqrt{20-20}\implies \sqrt{0}\implies 0

now, 0 is not negative, so the radicand is golden

BUT, if "x" has a value higher than 10/3, the radicand turns negative
for example  \bf x=\frac{11}{3}
\\\\\\

\sqrt{20-6\left( \frac{11}{3} \right)}\implies \sqrt{20-22}\implies \sqrt{-2}

so.. that's not a good value for "x"

thus, the domain, or values "x" can safely take on, are all real numbers from 10/3 onwards, or to infinity if you wish
5 0
4 years ago
How to find the vertex and axis of symmetry
strojnjashka [21]
Use the equation of -b/2a, so if you have a line you can just plug in the numbers.
3 0
3 years ago
The brand xyz dog food costs $36 for 15 pounds of dog food. What is the cost per pound?
HACTEHA [7]

Answer:

Step-by-step explanation:

36/$15 = $2.04 per pound

3 0
3 years ago
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