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ExtremeBDS [4]
2 years ago
11

HELP IM IN CLASS AND I NEED IT DONE TODAY!

Mathematics
1 answer:
Nesterboy [21]2 years ago
6 0

Answer:

<h2><u><em>at x = 3      D = .1086</em></u></h2><h2><u><em /></u></h2><h2><u><em>at x = 4      D =  .0869</em></u></h2><h2><u><em /></u></h2><h2><u><em>at x = 5      D = .0724</em></u></h2>

<u><em /></u>

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Express the confidence interval (0.432, 0.52 in the form of ±<br> e.
lakkis [162]
For a known standard deviation, the confidence interval for sample size = n is
(x-z \frac{ \sigma }{ \sqrt{n}},x+x \frac{ \sigma }{ \sqrt{n} }  )
where
x =  average
n = sample size
\sigma = stad. deviation
z = contant that reflects confidence interval

Let a = x
Let b = z \frac{ \sigma }{ \sqrt{n} }

From the given information,
a - b = 0.432          (1)
a + b = 0.52           (2)

Add (1) and (2): 2a = 0.952  =>  a = 0.476
Subtract (2) from (1): -2b = -0.088  => b = 0.044

Therefore, the confidence interval may be written as
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4 0
3 years ago
Given: △ABC, m∠C=90° m∠ABC=30°, AL ∠ bisector CL=6 ft. Find: LB
vlada-n [284]

For a better understanding of the solution given here please go through the diagram in the file attached.

To solve this question we will make use of the "Triangle Angle Bisector Theorem", which states that, "An angle bisector of an angle of a triangle divides the opposite side in two segments that are proportional to the other two sides of the triangle."

Thus, in our question, we will have:

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The above equation can be rearranged as:

LB=CL\times \frac{AB}{AC}=\frac{CL}{(\frac{AC}{AB})}...(Equation 1)

If we have a proper look at the denominator which is \frac{AC}{AB}, we note that in \Delta ABC, \frac{AC}{AB}=Sin(\angle ABC)=Sin(30^\circ)

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3 0
3 years ago
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Dahasolnce [82]

Step-by-step explanation:

But you can search on other applications

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3 years ago
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