Answer: X'(-3, -2), Y'(-5, 1), and Z'(2, -3)
Step-by-step explanation:
Upon reflection across the x-axis, the x-coordinates remain the same while the signs of the y-coordinates flip. So, the coordinates will be X(3, -2), Y(5, 1), and Z(-2, -3).
Upon reflection across the y-axis, the signs of the x-coordinates will flip while the signs of the y-coordinates remain the same. So, the coordinates will be X′(-3, -2), Y′(-5, 1), and Z′(2, -3).
Answer: sounds interesting
Step-by-step explanation:
P(Al hits bottle first time) = 1/3
P(Al misses the first shot but hits on his second shot) =
P( Al misses and bill misses and Al hits) = 2/3 * 3/4 * 1/3 = 1/6
So required probability = 1/3 + 1/6 = 1/2
<span>g(x) = x^2 + 3x - 4 (please be sure to use " ^ " to denote exponentiation).
This function factors into g(x) = (x+4)(x-1), and so the zeros are -4 and +1.
If we shift this graph 5 units to the left, we get h(x) = (x+5)^2 + 3(x+5) - 4.
The new zeros will be -4-5 and 1-5, or -9 and -4.
</span>
Answer:

Step-by-step explanation:
I will assume the following:
- You know how to use the quadratic formula
- You know how to simplify radicals
- You know how to use the pythagorean theorem.
The challenge of this exercise comes from using the pythagorean theorem and setting up a few equations.
Given that we have a segment 36 units long and another segment that is 16, it is trivial to get the other segment, 20. Additionally, there are two sides that I want to name so that way I can make a couple of substitutions. I will call these side a and side b. (see attachment 1)
Now comes with setting up three equations. I will start with the two smaller triangles, using side a and side b. See attachments 2 and 3.
Now with the big triangle. I will set up one last equation. See attachment 4.
Given what we know about attachment 2 and 3, we can make two substitutions. See attachment 5. I assume you know how to do the rest and arrive at your only real solution.