What is the area of a wall that is 28' wide by 10' high at the sides and has a triangular gable that measures 7' high?
1 answer:
Answer:
378 ft²
Step-by-step explanation:
Given:
The Width of the wall = 28'
The Length of the wall = 10'
The Height of the gable = 7'
Now, the width of the gable will be equal to the width of the wall = 28'
therefore,
Area of the wall = Area of the rectangle section of wall + area of the gable
Total area of the wall = ( 28' × 10' ) + ( )
or
Total area of the wall = 280 + 98 = 378 ft²
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point slope formula y - y1 = m(x - x1)
use (0, -3)
y - (-3) = 1 (x -0)
y + 3 = 1x