Question

What is the area of a wall that is 28' wide by 10' high at the sides and has a triangular gable that measures 7' high?

Answer 1

Answer:

378 ft²

Step-by-step explanation:

Given:

The Width of the wall = 28'

The Length of the wall = 10'

The Height of the gable = 7'

Now, the width of the gable will be equal to the width of the wall = 28'

therefore,

Area of the wall = Area of the rectangle section of wall + area of the gable

Total area of the wall = ( 28' × 10' ) + ( $\frac{1}{2}\times28'\times7'$)

or

Total area of the wall = 280 + 98 = 378 ft²