What is the area of a wall that is 28' wide by 10' high at the sides and has a triangular gable that measures 7' high?
1 answer:
Answer:
378 ft²
Step-by-step explanation:
Given:
The Width of the wall = 28'
The Length of the wall = 10'
The Height of the gable = 7'
Now, the width of the gable will be equal to the width of the wall = 28'
therefore,
Area of the wall = Area of the rectangle section of wall + area of the gable
Total area of the wall = ( 28' × 10' ) + ( )
or
Total area of the wall = 280 + 98 = 378 ft²
You might be interested in
Answer:
Step-by-step explanation:
In order to solve this problem, let's first understand what the question is asking.
If we combine Solution A (with 35% salt) and Solution B (with 85% salt), our goal is to create a 40 ounce mixture with 45% salt.
Let's model an equation for this, assuming that a is the amount of ounces of Solution A and b is the amount of ounces of Solution B.
<em>Why?</em> Since 35% of a number is the same as multiplying it by 0.35, we can multiple the total number of ounces by the decimal to find how many ounces of it will contain salt.
We also know that we need 40 ounces of this mixture. Therefore, adding together Solution A and B must get 40:
We can now solve this systems of equations.
Now that we know Solution B needs 8 ounces of mixture, we can substitute it into an equation to solve for a.
Therefore, we need 32 ounces of Solution A and 8 ounces of Solution B.
Hope this helped!