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vivado [14]
3 years ago
7

What is the area of a wall that is 28' wide by 10' high at the sides and has a triangular gable that measures 7' high?

Mathematics
1 answer:
Karolina [17]3 years ago
7 0

Answer:

378 ft²

Step-by-step explanation:

Given:

The Width of the wall = 28'

The Length of the wall = 10'

The Height of the gable = 7'

Now, the width of the gable will be equal to the width of the wall = 28'

therefore,

Area of the wall = Area of the rectangle section of wall + area of the gable

Total area of the wall = ( 28' × 10' ) + ( \frac{1}{2}\times28'\times7')

or

Total area of the wall = 280 + 98 = 378 ft²

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Sati [7]

Answer:

\huge\boxed{y=-\dfrac{1}{4}x-1\to x+4y=-4}

Step-by-step explanation:

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\text{Lines are to be parallel. Therefore}\ m_2=-\dfrac{1}{4}.\\\\\text{We initially have the form equation}\ y=-\dfrac{1}{4}x+b.\\\\\text{The line passes through the point}\ (9,\ -3).\\\\\text{Substitute the coordinates of the point to the equation of a line:}\\\\x=9,\ y=-3\\\\-3=-\dfrac{1}{4}(9)+b\\\\-3=-\dfrac{9}{4}+b\qquad\text{add}\ \dfrac{9}{4}\ \text{to both sides}\\\\-\dfrac{12}{4}+\dfrac{9}{4}=b\to b=-\dfrac{3}{4}

\text{Lines are to be parallel. Therefore}\ m_2=-\dfrac{1}{4}.\\\\\text{We initially have the form equation}\ y=-\dfrac{1}{4}x+b.\\\\\text{The line passes through the point}\ (8,\ -3).\\\\\text{Substitute the coordinates of the point to the equation of a line:}

x=8,\ y=-3\\\\-3=-\dfrac{1}{4}(8)+b\\\\-3=-2+b\qquad\text{add 2 to both sides}\\\\-1=b\to b=-1

\text{Therefore the equation is:}\ y=-\dfrac{1}{4}x-1.\\\\\text{Convert to the standard form}\ Ax+By=C:\\\\y=-\dfrac{1}{4}x-1\qquad\text{multiply both sides by 4}\\\\4y=-x-4\qquad\text{add}\ x\ \text{to both sides}\\\\x+4y=-4

5 0
3 years ago
8. If the measure of one side of a square is increased by 2 centimeters and the measure of
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Answer:

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Step-by-step explanation:

If the original side length is x, then the modified square has an area of ...

  A = LW

  32 = (x +2)(x -2) = x^2  -4

  36 = x^2 . . . . . . . . add 4

  6 = x . . . . . . . . . . take the square root

The original figure has a side length of 6 cm.

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<em>Check</em>

The modified figure is 8 cm by 4 cm = 32 cm^2.

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Answer:

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Step-by-step explanation:

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2 years ago
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Given :

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