4 years ago

Which value would be a solution for × in the inequality 47-4×<7

Mathematics

1 answer:

Bad White [126]4 years ago

6 0

Step-by-step explanation:

47-4x<7

-4x<7-47

-4x<-40

x>(40÷4)

x>10

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REY [17]

The true statement about the graph of the function f(x) = x3 - 2x2 + 4x – 8 is (B) The function has 1 real zero that occurs 1 time.

<h3>How to determine the true statement</h3>

The function of f(x) is represented as:

$f(x)=x^3-2x^2+4x-8$

Differentiate the function f(x)

$f'(x)=3x^2-4x+4$

Calculate the minimum value using:

$x = -\frac b{2a}$

So, we have:

$x = -\frac {-4}{2*3}$

$x = \frac {2}{3}$

Substitute 2/3 in f'(x)

$f'(2/3)=3*(2/3)^2-4(2/3)+4$

$f'(2/3)=\frac 83$

The value of f'(2/3) is greater than 0.

This means that the function f(x) has 1 real zero, and it occurs once at point (2,0)

Hence, the true statement is (b)

Read more about functions at:

brainly.com/question/13136492

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Find the equation of the line passing through the point (1, 7) with a slope of -2.

Mariulka [41]

Answer:

$y=-2x+9$

Step-by-step explanation:

we know that

The equation of a line in point slope form is equal to

$y-y1=m(x-x1)$

In this problem we have

$(x1,y1)=(1,7)\\m=-2$

substitute

$y-7=-2(x-1)$

Convert to slope intercept form

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$y-7=-2x+2$

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