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Simora [160]
2 years ago
13

Pls pls pls pls pls help me pls thanks

Mathematics
2 answers:
Marta_Voda [28]2 years ago
4 0

Answer:

145

-36

48

Please mark me as the brainliest

dalvyx [7]2 years ago
3 0

<u>Note</u><u>→</u><u> </u><u>Put</u><u> </u><u>all</u><u> </u><u>the</u><u> </u><u>value</u><u> </u><u>in</u><u> </u><u>alphabet</u><u>.</u>

◆ p^2 + 4q^2 = 145

◆mn/-4p = -36

◆b^2c/ad^2 = -48

I hope it's help you...

Mark me as brainliest...

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2 Quick algebra 1 question for 50 points!
SVETLANKA909090 [29]

#6

Yes

Direct variation because Time increases cupcakes increases and vice versa

#B

Constant of proportionality represents the amount of time required per cupcakes

#7

Yes we can find it

We have to check the x and y values of the ordered pairs (x,y)

If y is decreasing with respect to increase in x then it's inverse variation

3 0
2 years ago
Solve the following systems by Elimination
Alenkasestr [34]

Answer:

The solutions for both system of equations are as follows:

  1. (5,2)
  2. (2,-1)

Step-by-step explanation:

The first set of equations is:

4x+6y=32\\3x-6y=3\\

It can clearly be seen that the coefficients of y are already same in magnitude with different signs so we have to add both equations

So adding both equations, we get

4x+6y+3x-6y = 32+3\\7x = 35\\\frac{7x}{7} = \frac{35}{7}\\x = 5

Putting x=5 in equation 1

4(5)+6y = 32\\20+6y = 32\\6y = 32-20\\6y = 12\\\frac{6y}{6} = \frac{12}{6}\\y = 2

The solution is (5,2)

The second set of simultaneous equations is:

-3x+5y=-113x+7y=-1

We can see that the coefficients of x in both equations are same in magnitude with opposite signs so

Adding both equations

-3x+5y+3x+7y = -11-1\\12y = -12\\\frac{12y}{12} = \frac{-12}{12}\\y = -1

Putting y= -1 in first equation

-3x+5(-1)=-11\\-3x-5=-11\\-3x=-11+5\\-3x=-6\\\frac{-3x}{-3} = \frac{-6}{-3}\\x = 2

The solution is: (2,-1)

Hence,

The solutions for both system of equations are as follows:

  1. (5,2)
  2. (2,-1)
3 0
2 years ago
Please help me with these
Alex Ar [27]
When we approach limits, we are finding values that are infinitesimally approaching this x-value. Essentially, we consider the approximate location that this root or limit appears. This is essential when it comes to taking Calculus, and finding the limit or rate of change of a function.

When we are attempting limits questions, there are several tests we attempt first.

1. Evaluate the limit by substituting the value of the x-value as it approaches the value (direct evaluation of a limit)
2. Rearrangement of the function, such that we can evaluate the limit.
3. (TRIGONOMETRIC PROPERTIES)
\lim_{x \to 0} (\frac{sinx}{x}) = 1
\lim_{x \to 0} (\frac{tanx}{x}) = 1
4. Using L'Hopital's Rule for indeterminate limits, such as 0/0, -infinity/infinity, or infinity/infinity.

For example:

1) \lim_{x \to 0}\frac{\sqrt{x} - 5}{x - 25}

We can do this using the first and second method.
<em>Method 1: Direct evaluation:</em>

Substitute x = 0 to the function.
\frac{\sqrt{0} - 5}{0 - 25}
= \frac{-5}{-25}
= \frac{1}{5}

<em>Method 2: Rearranging the function
</em>

We can see that x - 25 can be rewritten as: (√x - 5)(√x + 5)
By rewriting it in this form, the top will cancel with the bottom easily, and our limit comes out the same.

\lim_{x \to 0}\frac{(\sqrt{x} - 5)}{(\sqrt{x} - 5)(\sqrt{x} + 5)}
= \lim_{x \to 0}\frac{1}{(\sqrt{x} + 5)}}
= \frac{1}{5}

Every example works exactly the same way, and by remembering these criteria, every limit question should come out pretty naturally.
8 0
3 years ago
A town has a population of 32,000 in the year 2002; 35,200 in the year 2003; 38,720 in the year 2004; and 42,592 in the year 200
Romashka-Z-Leto [24]
The answer is 102,442
3 0
3 years ago
Add<br>(4-4i)+(3-2i)<br>Write as complex number in standard form​
Viefleur [7K]

Answer: (4-4i)+(3-2i) = 7-6i

Step-by-step explanation:

To add or subtract two complex numbers, just add or subtract the corresponding real and imaginary parts. For instance, the sum of 4 -4i and 3 - 2i is 7 -6i. The numbers in standard form will be a + bi, where a is the real part and bi is the imaginary part.

8 0
3 years ago
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