Answer:
A. The median weight for shelter A is greater than that for shelter B.
D. The data for shelter B are a symmetric data set.
E. The interquartile range of shelter A is greater than the interquartile range of shelter B.
Step-by-step explanation:
ty for the ptsss
Answer:
If y(t) is the mass (in mg) remaining after t years, then y(t) = y(0) (0.5)^{t/T} = 400 (0.5)^{t /4}, where T is the half-life period and y(0) is the amount at t = 0 years (initial).
Then at t = 20:
y(20) = 400 (0.5)^{20 /4} = \text{12.5 mg}
Step-by-step explanation:
Answer:
114.58 pounds
Step-by-step explanation:
33.7 x 3.4 = 114.58
n, n + 2, n + 4 - three consecutive odd integers
366 - the sum
Equation:
n + (n + 2) + (n + 4) = 366
n + n + 2 + n + 4 = 366
3n + 6 = 366 |subtract 6 from both sides
3n = 360 |divide both sides by 3
n = 120
n + 2 = 120 + 2 = 122
n + 4 = 120 + 4 = 124
Answer: 120, 122, 124.
