Which expression is the factored form of −1.5w+7.5 ?

Find the value of x. Round your answer to the nearest tenth

enot [183]

hi I am interested for your answers but I can't find 5x-3 in my profile as my number and I am currently in my second week and simplify days of my contract for my current role 

the following 3x are some numbers for you and your answers will not care for you and your answers to all of the boxes in my number of days 

4 0

3 years ago

What fraction is equivalent to the decimal and percent below? Enter your

Anna11 [10]

Answer: 1/2

Step-by-step explanation:

6 0

3 years ago

Find LCM of: x2 - 9, 3x3 + 81

VikaD [51]

Answer:

$\boxed{\pink{\sf (x + 3) \ is\ the \ LCM . }}$

Step-by-step explanation:

Given two expressions ,

$\qquad (1)\: x^2 - 9 \\\\ \qquad (2)\:3x^3 + 81$

And , we need to find the LCM , that is lowest common factor . So , let's factorise them seperately .

Factorising x² - 9 :- 

$= x^2 - 9 \\\\= x^2 - 3^2 \\\\ \red{= (x+3)(x-3)} \qquad\bf [Using \ a^2-b^2 = (a+b)(a-b) ]$

Factorising 3x³ + 81 

$= 3x^3 + 81\\\\= 3(x^3+27) \\\\= 3( x^3+27) \\\\ = 3(x^3+3^3) \\\\ \red{= 3 [ (x+3)(x^2+9-3x) ] } \qquad \bf{[ Using \ a^3+b^3=(a+b)(a^2+b^2-ab) ] }$

Hence we can see that (x+3) is common factor in both expressions.

Hence the LCM is ( x+3 ) .

8 0

3 years ago

What is y= 4^x with the domain of (-2,0,3)

Elena L [17]

Step-by-step explanation:

$\text{Put}\ x=-2,\ x=0\ \text{and}\ x=3\ \text{to the equation}\ y=4^x:\\\\y=4^{-2}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\y=\dfrac{1}{4^2}=\dfrac{1}{16}\\-----------------\\\\y=4^0=1\\-----------------\\\\y=4^3=64$

7 0

4 years ago

A cookie company packages its cookies in rectangular prism boxes designed with square bases that have both a length and width of

Verdich [7]

Answer:

length and width=4

height=8

Step-by-step explanation:

Hello to solve this problem we must propose a system of equations of 3x3, that is to say 3 variables and 3 equations.

Ecuation 1

Leght=Width

.L=W

Ecuation 2

To raise the second equation we consider that the length and width of 4 inches less than the height of the box

H-4=W

Ecuation 3

To establish equation number 3, we find the volume of a prism that is the result of multiplying length, width, and height

LxWxH=128

From ecuation 1(w=h)

$HW^2=128$

solving for H

$H=\frac{128}{W^2}$

Using ecuation 2

H-4=W

$\frac{128}{W^2}-4=W\\W^3+4W^2-128=0$

Now we find the roots of the equation, 2 of them are imaginary, and only one results in 4

W=4in

L=4in

to find the height we use the ecuation 2

H-4=W

H=4+W

H=4+4=8

H=8IN

7 0

3 years ago