Let's plug in each coordinate and see what we get:
(2, 0, 0)
-> 2A + 0 + 0 = D
-> 2A = D
-> A = D/2
(0, 6, 0)
-> 0 + 6B + 0 = D
-> 6B = D
-> B = D/6
(0, 0, 5)
-> 0 + 0 + 5C = D
-> 5C = D
-> C = D/5
plugging this back into the equation:
(D/2)x + (D/6)y + (D/5)z = D [then divide through by D]
(1/2)x + (1/6)y + (1/5)z = 1
and since we have to have integer coefficients,
multiply through by 30
so we get
15x + 5y + 6z = 30
Second question
<span>Take a look at the bottom-left point in the picture.
If you move three points in the y-direction, you'll reach to the point A.
If you instead move up 4 points (or in the z-direction), you reach D.
And finally, if you walk back to point F from point E, you'll have moved back 4 points in the x direction. </span>
<span>This gives us our measurements, or dimensions: 3 x 4 x 4.
If this were a rectangular prism, the dimensions would just be each of them multiplied.
But since it's triangular, you need to divide it by two. That gives you a total volume of
(3x4x4)/2 = 24.</span>
Answer:
I would say A
Step-by-step explanation:
hmu if you need more help
the solution is here,
the coordinate of centre of circle A is (3,2)
and the coordinate of centre of circle B is (3,0).
so the translation point from A to B is (3-0,0-2)=(3,-2).
Now the translation rule is given by (x+h,y+k)
where h is the tranalation anlong the x-axis and k is the translation along the y-axis.
For this problem, translation ruleis (x+3,y-2).
Then, radius of circle A(r1)=2 units
radius of circle B (r2)= 3 units
as the circle A is translated to B, the scale factor is
r2/r1=3/2=1.5
In conclusion, the translation rule for given circles is (x+3,y-2) and its scale factor is 1.5
Hope This helps you..!!!!
Answer:
r=1/π
Step-by-step explanation:
Area of the circle is defined as:
Area = πr²
Derivating both sides
=2πr
=
x
= 2πr![\frac{dr}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7Bdr%7D%7Bdt%7D)
If area of an expanding circle is increasing twice as fast as its radius in linear units. then we have :
=2![\frac{dr}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7Bdr%7D%7Bdt%7D)
Therefore,
2πr
= 2 ![\frac{dr}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7Bdr%7D%7Bdt%7D)
r=1/π