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Cerrena [4.2K]
3 years ago
11

PLEASE HELP I CANT CONTINUE WITH MY WORK UNLESS THESE ARE COMPLETE AND CORRECT

Mathematics
1 answer:
Snezhnost [94]3 years ago
6 0

Answer:

1) x=3, y=-3

Step-by-step explanation:

10x + 7y = 9 —— (1)

-4x -7y = 9 —— (2)

(1) + (2)

6x = 18

x = 18/6

x = 3

put x=3 in (1)

10(3) + 7y = 9

30 + 7y = 9

7y = 9 - 30

7y = -21

y = -21/7

y = -3

please give me brainlist if it is helpful for you

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Completely factor 7x^2 - 4x - 3
kondor19780726 [428]

Answer:

(7x+3) (x-1)

hope this helps!!:)

Step-by-step explanation:

3 0
3 years ago
F(x)=-12x - 2x + 60x² +14x-60
Leona [35]

Answer:

x=±1. are the factors of the quadratic equation.

Step-by-step explanation:

Given quadratic expression, f(x)=-12x - 2x + 60x² +14x-60

Rearranging and adding the terms in the expression and equating to zero.

f(x)= 60x² -60=0

60(x² - 1) =0

The zero product property states that if the product of a⋅b=0 then either a or b equal zero or both of them must be equal to zero. This basic property helps us solve the quadratic equations like (x+2)(x-5)=0 where x =-2,5.

from the zero product property we can infer that 60≠0⇒x² - 1=0

⇒(x+1)×(x-1) = 0

⇒x=±1.

Therefore, x=±1. are the factors of the quadratic equation.

3 0
3 years ago
Help me please anyone!
olasank [31]

Answer:

1) 13(2) + 2m = A

2) 70

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
X+5.5+8=5x-13.5-4x what does x equal
wariber [46]

Answer:

There are no values of x that makes the equation true. or in other words ( no solution)

8 0
3 years ago
Let $f(x)$ be the real-valued function defined for all real $x$ except for $x = 0$ and $x = 1$ and satisfying the functional equ
Mademuasel [1]
We have to find the values of F.
In this case. F is unlikely to be a polynomial.
But the problem is, we can’t calculate the values of F directly.
There is no real value of x for which x = x−1 x because F isn’t defined at 0 or 1. so,
substituting x = 2.
F(2) + F(1/2) = 3.

Substitute, x = 1/2
F(1/2) + F(−1) = −1/2.
We still are not getting the required value,
therefore,
Substitute x = −1

As, F(2) +F(−1) = 0.
now we have three equations in three unknowns, which we can solve.
It turns out that:
F(2) = 3/4
F(3) = 17/12
F(4) = 47/24
and
F(5) = 99/40

Setting
g(x) = 1 − 1/x
and using
2 → 1/2
to denote
g(2) = 1/2
 we see that :
x → 1 - 1/x → 1/(1-x) →x

so that:
g(g(g(x))) = x.

Therefore, whatever x 6= 0, 1 we start with, we will always get three equations in the three “unknowns” F(x), F(g(x)) and F(g(g(x))).
Now solve these equations to get a formula for F(x)

As,
h(x) = (1+x)/(1−x)
which satisfies h(h(h(h(x)))) = x

Now, mapping x to h(x) corresponds to rotating the circle by ninety degrees.

7 0
3 years ago
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