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andrew11 [14]
3 years ago
10

Consider three consecutive positive integers, such that the sum of the

Mathematics
1 answer:
Greeley [361]3 years ago
4 0

Answer:

  17

Step-by-step explanation:

Let x represent the smaller integer. Then we have ...

  (x +1)² +(x +2)² = 40x +5

  2x² +6x +5 = 40x +5

  x² -17x = 0 . . . . . subtract (40x+5), divide by 2

  x(x -17) = 0 . . . . . factor

The solution of interest is x = 17.

The smaller integer is 17.

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