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3 years ago

13

The equation cos(35) =a/25 can be used to find the length of bc

1 answer:

pishuonlain [190]3 years ago

8 0

Solve for a using the equation. Hope that helps!

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Help Please ASAP!<br> what is 7⋅8÷4⋅37⋅8÷4⋅3

Black_prince [1.1K]

7x8÷4x37x8÷4x3 = 3108/1 = 3108

7 0

3 years ago

A coin is to be tossed until a head appears twice in a row. What is the sample space for this experiment? If the coin is fair, w

blsea [12.9K]

Answer:

The sample space would be infinite

{HH, TTTHH, TTTTHH, TTTTTTTHH.......................}

1/8

Step-by-step explanation:

The sample space would be infinite

{HH, TTTHH, TTTTHH, TTTTTTTHH.......................}.

This is because the number of times the coin would be flipped is not specified. So, you can keep flipping the coin forever.

If the coin is tossed four times then the sample space would be

{HHHH HTHH THHH HTHT

HHHT HTTH TTHH THTH

HHTT HHTH TTTH THHT

HTTT TTTT TTHT THTT}

HTHH and TTHH are the only two cases where two consecutive tosses will result in two heads

Probability that the coin will be tossed four times is 2/16 = 1/8

6 0

3 years ago

On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

Elena L [17]

Answer:

The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, a = $\sqrt{(3-0)^{2}+(4-0)^{2}}$

Or, a = $\sqrt{9+16}$

Or, a = $\sqrt{25}$

∴ a = 5 unit

Similarly

The measure of length BC = b = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, b = $\sqrt{(3-3)^{2}+(2-4)^{2}}$

Or, a = $\sqrt{0+4}$

Or, b = $\sqrt{4}$

∴ b = 2 unit

And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, c = $\sqrt{(3-0)^{2}+(2-0)^{2}}$

Or, c = $\sqrt{9+4}$

Or, c = $\sqrt{13}$

∴ c = $\sqrt{13}$ unit

Now, area of Triangle written as , from Heron's formula

A = $\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

and s = $\frac{a+b+c}{2}$

I.e s = $\frac{5+2+\sqrt{13}}{2}$

Or. s = $\frac{7+\sqrt{13}}{2}$

So, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}$

Or, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}$

Or, A = $\frac{3}{2}$ × $\sqrt{1+\sqrt{13} }$

∴ Area of triangle = 1.5 $\sqrt{4.6}$

Hence The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$ Answer

7 0

3 years ago

Read 2 more answers

3. What three numbers are the Pythagorean triple generated by using 4 for x and 1 for y. Remember to use the formulas:

Gnom [1K]

Given:

The three equations for the three numbers are

$a=x^2-y^2$

$b=2xy$

$c=x^2+y^2$

To find:

The Pythagorean triple generated by using 4 for x and 1 for y.

Solution:

Substituting x=4 and and y=1 in the given equations, we get

$a=4^2-1^2$

$a=16-1$

$a=15$

In the same way find b and c.

$b=2(4)(1)$

$b=8$

The third number is

$c=4^2+1^2$

$c=16+1$

$c=17$

The required Pythagorean triple is 8, 15, and 17.

Therefore, the correct option is C.

5 0

3 years ago

Whats two integers that have an absoulute value of 10?

diamong [38]

Negative 10 and positive 10

4 0

3 years ago

Read 2 more answers