We have to find the correct statement for angle A in a triangle ABC,
which is an obtuse triangle. We know that angle B is obtuse ( greater
than 90 degrees ). Therefore angles A and C must be less than 90
degrees. Angle A can not be congruent to angle B ( angle B > angle A
). It can be congruent to angle C but just in case that ABC is an
isosceles obtuse triangle. Answer: Angle A must be A ) less than 90
degrees.
A thumb-wrestling match requires two thumbs, so we can either suppose that we need at least two people

, or allow one to thumb-wrestle one's self. In either case, we'd have

, so let's just say we need a minimum of two players.
If we add one more person to the set of players, then the first two people would need to play 1 additional match each. So

.
If we add one more person, then the first three people would again each have to play 1 more match with the new person. So

.
And so on, so that in general, the number of games needed for everyone to play exactly one match with everyone else is given recursively by
Answer:3/7
Step-by-step explanation: 3/7 x 7/3 = 21/21 = 1
I believe the answer is to be c
Answer:
B
Step-by-step explanation:
3 1/5 x 7/1
(3 x 5) + 1 = 16/5
16/5 x 7/1 = 112/5.
112 ÷ 5 = 22 2/5
so its B.